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mestny [16]
3 years ago
5

One pipe can fill a swimming pool in 8 hours. Another pipe takes 12 hours. How long will it take to fill the pool if both pipes

are used simultaneously?
Mathematics
1 answer:
Nookie1986 [14]3 years ago
5 0
For 4 h and 48 min. The first pipe fills the whole pool for 8 hours so from here we see that it fills 1/8 each hour. The second pipe fills it for 12 hours so it fills 1/12 each hour. Now both of them together fill 1/8 + 1/12 of the pool each hour. That equals: 1st pipe 3/24 of the pool each hour and the 2nd pipe 2/24 of the pool each hour. So, the two pipes together fill 3/24 + 2/24 each hour. That's 5/24 of the pool each hour.
1st hour: 5/24
2nd hour: 10/24
3rd hour: 15/24
4th hour: 20/24
And we need 4/24 more. So, if 5/24 is 1 h, then 1/24 is (60 minutes/5) 12 minutes. We need 4*1/24 and that is 12 minutes * 4 and that is 48 minutes.

So, they will fill the pool for 4 h and 48 min.
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The graph of f is given in the figure to the right. Let ​A(x)equals=Integral from 0 to x f left parenthesis t right parenthesis
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Answer:

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A(x)=\int\limits^x_0 f{x} \, dx

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A(4)=\int\limits^4_0 f{x} \, dx

Since, this curve is below x-axis

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Calculation of A(8):

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now, we can find area and then combine them

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Calculation of A(12):

we can plug x=12

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we can break into two parts

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now, we can find area and then combine them

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Calculation of A(14):

we can plug x=14

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we can break into two parts

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now, we can find area and then combine them

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