Answer:
first one is square root
don't know the second tho
Answer:
Step-by-step explanation:
Let us assume that if possible in the group of 101, each had a different number of friends. Then the no of friends 101 persons have 0,1,2,....100 only since number of friends are integers and non negative.
Say P has 100 friends then P has all other persons as friends. In this case, there cannot be any one who has 0 friend. So a contradiction. Hence proved
Part ii: EVen if instead of 101, say n people are there same proof follows as
if different number of friends then they would be 0,1,2...n-1
If one person has n-1 friends then there cannot be any one who does not have any friend.
Thus same proof follows.
Step-by-step explanation:
k=8.6
i think it is the right answer
If dey colinear then
AE=AC+CE
so if AE=x+50 and CE=x+32 then
x+50=AC+x+32
minus x both sides
50=AC+32
minus 32 both sides
18=AC
AC=18 units
