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Sphinxa [80]
3 years ago
9

A parallelogram has vertices A(0,4), B(2, 2), C(4,4),

Mathematics
1 answer:
OleMash [197]3 years ago
6 0

Answer:

yes, parallelogram ABCD is a square.

Step-by-step explanation:

Given information: ABCD is parallelogram with vertices A(0,4), B(2, 2), C(4,4), and D(2,6).

We need to check whether this parallelogram is a square or not.

The opposite side of a parallelogram are parallel and congruent. If the interior angles a parallelogram are right angles then the parallelogram is square.

Formula for slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

Now, find the slopes of each side.

m_{AB}=\dfrac{2-4}{2-0}=-1

m_{BC}=\dfrac{4-2}{4-2}=1

m_{CD}=\dfrac{6-4}{2-4}=-1

m_{AD}=\dfrac{6-4}{2-0}=1

The product of slopes of two perpendicular line is -1.

The product of slopes of any two consecutive sides is -1. It means all interior angles are right angle.

Therefore, the parallelogram ABCD is a square.

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If isosceles triangle ABC has a 130° angle at vertex B, which statement must be true?
scZoUnD [109]

Answer:

Option B m<ZA+m<ZB = 155° is correct option.

Step-by-step explanation:

We know that sum of angles of triangle is equal to 180°

And Isosceles triangle, 2 angles are same

So, let  Angle 1 = x

Angle 2 = x

Angle 3 = 130°

Finding values of angle x

x+x+130=180

2x=180-130

2x=50

x=25

So, Angle 1 = 25 °

Angle 2 = 25°

As, angle B is greater than 90°, the sum of angles added must be greater than 90°

So, Option A, C and D can't be correct, as their sum is less than 90°

Option B m<ZA+m<ZB = 155° is correct option.

Verify:

m<ZA = 25° (as found earlier)

m<ZB = 130° (given)

So, m<ZA+m<ZB = 155°

25°+130° = 155°

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Step-by-step explanation:

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Suppose we want to choose 7 colors, without replacement, from 9 distinct colors
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<h3>How to determine the number of ways?</h3>

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Colors to choose = 7

Since order does not matter, then it is combination

This is calculated using:

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This gives

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Evaluate

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