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Ierofanga [76]
1 year ago
9

Suppose we want to choose 7 colors, without replacement, from 9 distinct colors

Mathematics
1 answer:
Digiron [165]1 year ago
6 0

The number of ways to choose the colors is 36

<h3>How to determine the number of ways?</h3>

The given parameters are:

Colors = 9

Colors to choose = 7

Since order does not matter, then it is combination

This is calculated using:

^nC_r = \frac{n!}{(n - r)!r!}

This gives

^nC_r = \frac{9!}{7!2!}

Evaluate

^nC_r = 36

Hence, the number of ways is 36

Read more about combination at:

brainly.com/question/11732255

#SPJ1

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In the accompanying diagram of parallelogram ABCD,diagonals AC and DB intersect at E, AE = 3x - 4, andEC = x + 12.What is the va
skelet666 [1.2K]

x = 8

Explanation:

AE = 3x - 4

EC = x + 12

SInce diagonals AC and DB intersect at E

it means the lines which meet at the intersection E are equal. A and C meet at E which gives AE and EC

AE = EC

3x - 4 = x + 12

collect like terms:

3x - x = 12 + 4

2x = 16

divide both sides by 2:

2x/2 = 16/2

x = 8

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1 year ago
What is 2/3 + 3/4 or 2.3 + 3.4?
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2/3+3/4=17/12=1.417 This is the anwser
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3 years ago
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Answer:

5) moves one place to right

6) moves one place to left

Step-by-step explanation:

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3 0
2 years ago
Expand (2x -3y)^5 using the given formula.
horrorfan [7]
(2x-3y)^5

(2x-3y)(2x-3y)(2x-3y)(2x-3y)(2x-3y)

1st and 2nd power :
(2x-3y)(2x-3y) = 2x(2x-3y)-3y(2x-3y) = 4x² - 6xy - 6xy + 9y²
= 4x² - 12xy + 9y²

3rd power:
(2x-3y)(4x² - 12xy + 9y²) = 2x(4x² - 12xy + 9y²) - 3y(4x² - 12xy + 9y²)
8x³ - 24x²y + 18xy² - 12x²y +36xy² - 27y³
8x³ - 24x²y - 12x²y + 18xy² + 36xy² - 27y³
8x³ - 36x²y + 54xy² - 27y³

4th power
(2x-3y)(8x³ - 36x²y + 54xy² - 27y³) = 2x(8x³ - 36x²y + 54xy² - 27y³) -3y(8x³ - 36x²y + 54xy² - 27y³) = 16x^4 - 72x³y + 108x²y² - 54xy³ - 24x³y + 108x²y² - 162xy³ + 81y^4
16x^4 - 72x³y - 24x³y + 108x²y² + 108x²y² - 54xy³ - 162xy³ + 81y^4
16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4

5th power
(2x-3y)(<span>16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4)
2x(</span>16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4) - 3y(<span>16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4)
= 32x^5 - 192x^4y + 432x</span>³y² - 432x²y³ + 162xy^4 - 48x^4y + 288x³y² - 648x²y³ + 648xy^4 - 243y^5

32x^5 - 192x^4y -48x^4y + 432x³y² + 288x³y² - 432x²y³ - 648x²y³ + 162xy^4 + 648xy^4 - 243y^5

32x^5 - 240x^4y + 720x³y² - 1,080x²y³ + 810xy^4 - 243y^5
3 0
3 years ago
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