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Novay_Z [31]
3 years ago
6

PLEASE HELP ASAP!!!!!!!! Number 18 please a-f 

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
7 0
A. 80
b.100
c.80
d.80
e.20
f. 120

These are all in degrees.

Hope this helps. 
Foxeslair
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Suppose the scores of students on a Statistics course are Normally distributed with a mean of 563 and a standard deviation of 37
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Answer:

47.72% of students scored between 563 and 637 on the exam .

Step-by-step explanation:

The percentage of the students scored between 563 and 637 on the exam

= The percentage of the students scored lower than 637 on the exam -

the percentage of the students scored lower than 563 on the exam.

Since 563 is the mean score of students on the Statistics course, 50% of students scored lower than 563. that is P(x<563)=0.5

P(x<637)=P(z<z*) where z* is the z-statistic of the score 637.

z score can be calculated using the formula

z*=\frac{X-M}{s} where

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Then z*=\frac{637-563}{37} =2

P(z<2)=0.9772, which means that 97.72% of students scored lower than 637 on the exam.

As a Result, 97.72%-50%=47.72% of students scored between 563 and 637 on the exam

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