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3 years ago

Work out the perimeter of this quarter circle. Take Pi to be 3.142 and write down all the digits given by your calculator.

Mathematics

1 answer:

Ipatiy [6.2K]3 years ago

3 0

Answer:

Perimeter of the quarter circle will be 24.997 cm.

Step-by-step explanation:

Picture shown is a sector of a circle having an angle inscribed = 90° at the center

Formula to get the circumference of the sector is,

Circumference of the sector = $\frac{\theta^\circ}{360}(2\pi r)$

C = $\frac{90^\circ}{360^\circ}(2\pi)(7)$

C = $\frac{7\pi }{2}$

C = 10.997 cm

Now perimeter of the figure = Sum of lengths of all sides

P = 2r + C

P = 7 + 7 + 10.997

= 24.997 cm

Therefore, Perimeter of the quarter circle will be 24.997 cm.

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Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

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Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

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