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Vilka [71]
3 years ago
9

6+6 divided by 6/1-6

Mathematics
2 answers:
pav-90 [236]3 years ago
8 0

Answer:

The answer is 1.

Step-by-step explanation:

cricket20 [7]3 years ago
8 0
1 is the answer to the question
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A worker takes a random sample of 200 bolts and finds that 30 of them are either too long or Too Short thus making them unusable
Nutka1998 [239]

Answer:

B

Step-by-step explanation:

30 are unusable in 200. So how many are unusable in 17,000??

<em>We can set up a ratio and figure out the answer right away! Let x be the number of unusable bolts in 17,000, so we can write:</em>

<em>\frac{30}{200}=\frac{x}{17,000}\\200x=30*17000\\200x=510,000\\x=\frac{510,000}{200}\\x=2550</em>

<em />

<em>THus, number of unusable bolts is 2550. B is right.</em>

4 0
3 years ago
Can someone help me with this question?
Reil [10]

Answer:

3,512

Step-by-step explanation:

3,520-8=3,512

4 0
3 years ago
A paper airplane was thrown from the top of a tall building. The height of the paper airplane above the ground can be found usin
BaLLatris [955]

Answer:1) Since you have not provided the full question, I will work the quadratic expression that models the height of the paper airplane to find as much information as it gets.

2) Firstly, note that the quadratic function -2x^2 + 5x + 33 has these characteristics:

i) It is a parabola

ii) Since, the coefficient of x^2 is negative (-2) it opens downward and has a maximum, which indicates the maximum height of the airplane

iii) The, y-intercept, i.e. the y-value for x = 0, is the initial height of the ariplane, the height from which it was launched, and it is - 2 (0) + 5(0) + 33 = 33.

Then, the airplane was launched from a height of 33 units.

3) The vertex of the parabola is the maximum and it tells both the time to reach the maximum height and the value of that maximum.

4) You can easily find the vertex coordinates by completeing squares. This is how:

Start: -2x^2 + 5x + 33

Factor - 2 from the first two terms: - 2 (x^2 - 5/2x) + 33

Add and subtract the square of the half of x's coefficient:

- 2 ( x^2 - 5/2x + 25/16) + 25/8 + 33

Form the perfect square binomial: - 2 (x - 5/4)^2 + 289/8

By comparission with the vertex form of the equation of the parabola: A(x - h)² + k, the vertex is:

(h,k) = (5/4, 289/4) = (1.25, 36.125).

5) Then, the maximum height is 36.125 units, when the time is 1.25 seconds.

6) You can also find the time when the airplane lands on the ground by making -2x^2 + 5x + 33 = 0

For that you can factor the expression -2x^2 + 5x + 33

-2x^2 + 5x + 33 = - (x + 3) (2x - 11)

Equal to zero: - (x + 3)(2x - 11) = 0 ⇒ x = - 3 and x = 11/2 = 5.5.

That means that the airplane will land on the ground at 5.5 seconds.

7) You can also find the heights at different times, by just pluging in different values of x in the expression -2x^2 + 5x + 33.

7 0
3 years ago
Write a proof. Given x = 2 = 3 (x - 4) Prove x = 5
Galina-37 [17]

Step-by-step explanation:

The equation in the question is false.

x - 2 = 3(x - 4)

x - 2 = 3x - 12

3x - x = 12 - 2

2x = 10

x = 10 \div 2

x = 5

6 0
2 years ago
23
denpristay [2]

Answer:

Actual height of the building is 670 m

Step-by-step explanation:

We have been the actual height of a Ferris wheel which is 134 m. Along with it we are also given the scaled down heights of a Ferris wheel and a building. Using this data we have to find the actual height of a building.

Actual height of Ferris wheel = 134 m.

Height of Ferris wheel using the scale = 0.65 cm

Height of building after using the scale - 3.25 cm

Let, the actual height of building be x meters.

Since, the same scale is being used, the ratio of actual heights to that of scaled down heights must be the same for both objects.

i.e.

Ratio of Actual Height to scale height of Ferris Wheel = Ratio of Actual Height to scale height of the building

Using the values, we get:

134:0.65 =x:3.25\\\\\frac{134}{0.65}=\frac{x}{3.25}\\\\ \frac{134}{0.65} \times 3.25 = x\\\\  x=670

The units of actual heights are in meters, so this means the actual height of the building is 670 m

5 0
3 years ago
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