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irinina [24]
3 years ago
14

Multiple choice: 

Mathematics
1 answer:
Paha777 [63]3 years ago
7 0
In the given you wrote -2, whereas it should be -2i

z = a + bi and in trigo form | z |.(cos Ф + i.sin Ф).
z = 0 -2i → | z |.(cos Ф + i.sin Ф)
Now let's calculate z:
 
z² = a²+b² → z² = 0² (-2.i)² → z = -2(i)² →z= -2(-1) → z = |2|
tan Ф = b/a = -2/0 → tan Ф → - ∞ ↔ Ф = -90° or Ф = 270°
 then the - 2 I ↔ |2|(cos 270° + i.sin 270°)

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