All categories

4 years ago

How do you know if flammability is a chemical property

Chemistry

2 answers:

Tpy6a [65]4 years ago

7 0

Answer:

When a fuel burns, it combines with oxygen int the air and changes into the substances water and carbon dioxide.

Explanation:

snow_lady [41]4 years ago

5 0

When a fuel burns, it combines with oxygen int the air and changes into the substances water and carbon dioxide. That's how Flammability is a chemical property.

You might be interested in

What is the density of a bar of lead that weighs 173 g and has the following dimensions: l= 2.00 cm, w = 3.00 cm, h = 1.00 in?

oksano4ka [1.4K]

Answer:

$\rho=7373.2g/cm^3$

Explanation:

Hello!

In this case, since the density is defined as the degree of compactness of a substance, and is defined as the mass over the volume:

$\rho= \frac{m}{V}$

Given the dimensions of the bar of lead, we can compute the volume as shown below:

$V=2.00cm*3.00cm*1.00in*\frac{1in}{2.54cm} \\\\V=2.36cm^3$

Thus, the density turns out:

$\rho=\frac{173g}{2.36cm^3} \\\\\rho=7373.2g/cm^3$

Best regards!

8 0

3 years ago

What happens to crayons when heated?

Olin [163]

they become liquified

3 0

3 years ago

1. For the reaction 3A — C, the initial concentration of A was 0.2 M, and the reaction rate was

Andrew [12]

Answer:

$r=25M^{-1}s^{-1}[A]^2$

Explanation:

Hello there!

In this case, according to the given information for this chemical reaction, it is possible for us to set up the following general rate law and the ratio of the initial and the final (doubled concentration) condition:

$r=k[A]^n\\\\\frac{r_1}{r_2} =\frac{k[A]_1^n}{k[A]_2^n}$

Next, we plug in the given concentrations of A, 0.2M and 0.4 M, the rates, 1.0 M/s and 4.0 M/s and cancel out the rate constants as they are the same, in order to obtain the following:

$\frac{1.0}{4.0} =\frac{0.2^n}{0.4^n}\\\\0.25=0.5^n\\\\n=\frac{ln(0.25)}{ln(0.5)} \\\\n=2$

Which means this reaction is second-order with respect to A. Finally, we calculate the rate constant by using n, [A] and r, to obtain:

$k=\frac{r}{[A]^n} =\frac{1.0M/s}{(0.2M)^2}\\\\k=25M^{-1}s^{-1}$

Thus, the rate law turns out to be:

$r=25M^{-1}s^{-1}[A]^2$

Regards!

3 0

3 years ago

Convert 145 meters to kilometers.

Sphinxa [80]

Divide by 1000

145÷1000=0.145

Hope this will be helpful.

4 0

1 year ago

Gasoline is a mixture composed primarily of hydrocarbons such as isooctane, which is also known as 2,2,4-trimethylpentane.

morpeh [17]

Because of the 92% isooctane, the gasoline sample's octane rating is 92. The functional group in ethanol is the hydroxyl group.

3 0

3 years ago