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Zigmanuir [339]
4 years ago
10

Name the process occurring at B,and explain what results from it

Chemistry
2 answers:
babunello [35]4 years ago
6 0
Little is known of the language's prehistory, or when it first appeared in Japan. Chinese documents from the 3rd century recorded a few Japanese words, but substantial texts did not appear until the 8th century. During the Heian period (794–1185), Chinese had considerable influence on the vocabulary and phonology of Old Japanese. Late Middle Japanese (1185–1600) included changes in features that brought it closer to the modern language, and the first appearance of European loanwords. The standard dialect moved from the Kansai region to the Edo (modern Tokyo) region in the Early Modern Japanese period (early 17th century–mid-19th century). Following the end in 1853 of Japan's self-imposed isolation, the flow of loanwords from European languages increased significantly. English loanwords, in particular, have become frequent, and Japanese words from English roots have proliferated.

Japanese is an agglutinative, mora-timed language with simple phonotactics, a pure vowel system, phonemic vowel and consonant length, and a lexically significant pitch-accent. Word order is normally subject–object–verb with particles marking the grammatical function of words, and sentence structure is topic–comment. Sentence-final particles are used to add emotional or emphatic impact, or make questions. Nouns have no grammatical number or gender, and there are no articles. Verbs are conjugated, primarily for tense and voice, but not person. Japanese equivalents of adjectives are also conjugated. Japanese has a complex system of honorifics with verb forms and vocabulary to indicate the relative status of the speaker, the listener, and persons mentioned.

Japanese has no genetic relationship with Chinese,[3] but it makes extensive use of Chinese characters, or kanji (漢字), in its writing system, and a large portion of its vocabulary is borrowed from Chinese. Along with kanji, the Japanese writing system primarily uses two syllabic (or moraic) scripts, hiragana (ひらがな or 平仮名) and katakana (カタカナ or 片仮名). Latin script is used in a limited fashion, such as for imported acronyms, and the numeral system uses mostly Arabic numerals alongside traditional Chinese numerals.
ad-work [718]4 years ago
5 0

B comes before C in an alphabet,and after A:)

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A radioactive nuclide that is used for geological dating has an atomic number of 19 and mass number 40. Which is the symbol of t
Alina [70]
The mass number goes on top, and the atomic number goes on bottom. 
Therefore, the answer is C:
40
     K
19

7 0
4 years ago
Read 2 more answers
"Calculate the pH during the titration of 30.00 mL of 0.1000 M C3H7COOH(aq) with 0.1000 M LiOH(aq) after 29.9 mL of the base hav
Ivanshal [37]

Answer:

pH = 7.29

Explanation:

<em>Ka of butanoic acid is 1.54x10⁻⁵</em>

To obtain the pH of the solution you must use H-H equation for butanoic acid:

pH = pKa + log₁₀ [C₃H₇COO⁻] / [C₃H₇COOH]

Where pKa is defined as -log Ka = 4.81

Now, you need to find [C₃H₇COO⁻] and [C₃H₇COOH] concentrations (Also, you can find moles of each substance and replace them in the equation.

Butanoic acid reacts with LiOH, producing C₃H₇COO⁻, thus:

C₃H₇COOH + LiOH → C₃H₇COO⁻ + H₂O + Li⁺

Moles of both reactants, C₃H₇COOH and LiOH are:

C₃H₇COOH = 0.0300L ₓ (0.1000mol / L) = 0.003000moles of C₃H₇COOH

LiOH = 0.0299L ₓ (0.1000mol / L) = 0.00299 moles of LiOH.

That means moles of C₃H₇COO⁻ produced are <em>0.00299 moles</em>.

And moles of C₃H₇COOH that remains in solution are:

0.00300 - 0.00299 = <em>0.00001 moles of C₃H₇COOH</em>

Replacing in H-H equation:

pH = pKa + log₁₀ [C₃H₇COO⁻] / [C₃H₇COOH]

pH = 4.81 + log₁₀ [0.00299moles] / [0.00001moles]

<h3>pH = 7.29</h3>

7 0
4 years ago
When dissolving gases in water, the amount dissolving (decreases, does not change, increases) when the pressure is increased?
algol13
Increasing because more is being forced into liquid phase
4 0
4 years ago
In which one of the following pairs do the two species resemble each other most closely in chemical properties: (a) 1H1 and 1H1+
Delvig [45]

Answer:

c.        ₆¹²C   and   ₆¹³C

Explanation:

Properly writing the given options:

  a.   ₁¹H    and    ₁¹H⁺

  b.    ₇¹⁴N    and    ₇¹⁴N³⁻

  c.     ₆¹²C   and   ₆¹³C

Electrons are the crux of chemical reactions. These negatively charged subatomic particles determines chemical properties of atoms and how they combine with other atoms.

Atoms having the same number of electrons especially in their valence shells shares similar chemical properties.

From the problem above, we have been given some information about the atom.

The mass number is given by the superscript before the symbol of the atom and it signifies the sum of the number of protons and neutrons in the atom.

The atomic number is shown by the subscript and it denotes the number of protons in the atom.

For neutral atoms that has not lost or gained any additional electron, the atomic number is the same as the number of electrons.  

The superscript after the atom is the charge on the particle. It represents the number of electrons lost or gained by the atom.

In {c.  ₆¹²C   and   ₆¹³C}, the atom is in a neutral state. Here the atomic number which is 6 is the number of protons in the atom. This is also the number of electrons in the atom. Therefore, the two atoms would have similar chemical properties and behavior.

This is not so for the others as their number electrons are different.

8 0
4 years ago
A plant fertilizer contains 19 % nitrogen (N) by mass. In a container of soluble plant food, there are 10.0 oz of fertilizer. Ho
Evgesh-ka [11]

Answer:

53.87g

Explanation:

Given parameters:

Percentage by mass of Nitrogen in fertilizer = 19%

Mass of fertilizer = 10.0oz

Unkown:

Mass in grams of Nitrogen in the container = ?

Solution

To solve this problem, we first find the percentage of mass of nitrogen in the fertilizer by a taking a percentage of the given mass of the fertlilizer:

Mass of Nitrogen in ounces of the fertilizer =

                                             \frac{19}{100} x 10 = 1.9oz

Since we are expected to express this in grams:

         1oz = 28.35g

         1.9oz = 1.9 x 28.35, 53.87g

8 0
3 years ago
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