3 years ago

What is the pressure of 0.540 mol of an ideal gas at 35.5 L and 223 K?

1 answer:

4 0

P: ?
V: 35,5L = 35,5 dm³
n: 0,54 mol
R: 83,14 hPa·dm³/mol·K
T: 223K
..................
pV = nRT
p = nRT/V
p = (0,54×83,14×223)/35,5
p = 282,02 hPa

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