Well I figured out at his current pace, he would finish the 1100 remaining meters in 200 seconds. However, he needs to complete it in 180 seconds. I'm not sure how to find out how long he has to accelerate at 0.20 m/s/s to complete it in 180 seconds.
Gravitational acceleration is approx 9.8 m/s
Time is 7s
a=9.8 m/s
t=7s
a = d/t^2
therefore:
d = a * t^2
d = 9.8 * 7^2
d = 9.8 * 49
d = 480.2 [m]
Answer:
The distance is shortenend by factor .1715
Explanation:
5 n = 1/r^2
sqrt (1/5) = r
170 n = 1 / ( x sqrt(1/5))^2
(xsqrt 1/5)^2 = 1/170
x sqrt 1/5 = .076696
x = .1715
Answer:
we have τ = I * α as the rotational equation of motion
and we also have τ = F * r
so the torque τ = 5* 0.16 Nm = 0.8 Nm
from your plot of θ vs T^2 , calculate the slope of the line
this slope will be angular acceleration α.
Then you get I = τ/α
Explanation:
