consider the forces on mass m₁ on the incline plane :
parallel to incline , force equation is given as
T - m₁ g Sin30 = m₁ a
T = m₁ g Sin30 + m₁ a eq-1
consider the force on mass m₂ on the incline plane :
m₂ g - T = m₂ a
T = m₂ g - m₂ a eq-2
Using eq-1 and eq-2
m₂ g - m₂ a = m₁ g Sin30 + m₁ a
inserting the values
(2.3 x 9.8) - 2.3 a = (3.7 x 9.8) Sin30 + 3.7 a
a = 0.74 m/s²
Initial speed(u)=0m/s
Final speed(v)= 27m/s
Time(t)=7.6s
Use the equation of motion: v = u + at
27 = 0 + a(7.6)
27/7.6 = a
a = 3.55 m/s^2 (3 s.f)
1) 
The capacitance of a parallel-plate capacitor is given by:

where
is the vacuum permittivity
A is the area of each plate
d is the distance between the plates
Here, the radius of each plate is

so the area is

While the separation between the plates is

So the capacitance is

And now we can find the energy stored,which is given by:

2) 0.71 J/m^3
The magnitude of the electric field is given by

and the energy density of the electric field is given by

and using
, we find

Answer:
False
Explanation:
The Concentration of Acid or Base is the ph of the solution.
(A) We can solve the problem by using Ohm's law, which states:

where
V is the potential difference across the electrical device
I is the current through the device
R is its resistance
For the heater coil in the problem, we know

and

, therefore we can rearrange Ohm's law to find the current through the device:

(B) The resistance of a conductive wire depends on three factors. In fact, it is given by:

where

is the resistivity of the material of the wire
L is the length of the wire
A is the cross-sectional area of the wire
Basically, we see that the longer the wire, the larger its resistance; and the larger the section of the wire, the smaller its resistance.