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denis-greek [22]
3 years ago
8

The Gaia hypothesis is an example of _____

Physics
1 answer:
Fofino [41]3 years ago
4 0
A complex entity involving the Earth's biosphere, atmosphere, oceans, and soil; the totality constituting a feedback or cybernetic system which seeks an optimal physical and chemical environment for life on this planet
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A planet's moon travels in an approximately circular orbit of radius 7.0 ✕ 10⁷ m with a period of 6 h 38 min. Calculate the mass
natka813 [3]

Answer:

3.56×10²⁶ Kg.

Explanation:

Note: The gravitational force is acting as the centripetal force.

Fg = Fc........................... Equation 1

Where Fg = gravitational Force, Fc = centripetal force.

Recall,

Fg = GMm/r²......................... Equation 2

Fc = mv²/r............................. Equation 3

Where M = mass of the planet, m = mass of the moon, r = radius of the orbit and G = Universal gravitational constant.

Substituting equation 2 and 3 into equation 1

GMm/r² = mv²/r

Simplifying the equation above,

M = v²r/G .............................. Equation 4.

The period of the moon in the orbit

T = 2πr/v

Making v the subject of the equation,

v = 2πr/T............................. Equation 5

where r = 7.0×10⁷ m, T = 6 h 38 min = (6×3600 + 38×60) s = (21600+2280) s

T = 23880 s, π = 3.14

v = (2×3.14×7.0×10⁷ )/23880

v = 18409 m/s

Also Given: G = 6.67×10⁻¹¹ Nm²/kg²

Also substituting into equation 4

M = 18409²×7.0×10⁷ /(6.67×10⁻¹¹)

M = 3.56×10²⁶ Kg.

Thus the mass of the planet =  3.56×10²⁶ Kg.

5 0
3 years ago
A backpack weighs 8.2 newtons and has a mass of 5kg on the moon. What is the strength of the gravity on the moon?
Pavel [41]
Weight is equivalent to the product of the mass of an object and the strength of the gravitational field.

Using:
F = ma

a = 8.2 / 5
a = 1.64 N/kg

The gravitational field strength is equivalent to 1.64 N/kg.
7 0
3 years ago
Answer me nowwwwwwww
qwelly [4]

Answer:

volume

Explanation:

it depends on the volume of the items

hope this helps

8 0
3 years ago
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Consider the hydrogen atom as described by the Bohr model. The nucleus of the hydrogen atom is a single proton. The electron rot
riadik2000 [5.3K]

To solve this problem we will apply the concept of centripetal acceleration. This type of acceleration is described as the product between the square of the angular velocity and the turning radius. Mathematically the expression can be expressed as

a_c = \omega^2 r

Here,

\omega =Angular velocity

r = Radius

Our values are given as,

\omega = 4.12*10^{16}rad/s

r = 5.29*10^{-11}

Replacing,

a_c = (4.12*10^{16})^2( 5.29*10^{-11})

a_c = 8.979*10^{22}m/s^2

Therefore the electron's centripetal acceleration is 8.979*10^{22}m/s^2

7 0
3 years ago
Match: The graph below shows the potential and kinetic energy curves for a pendulum. Label each pendulum image with the correspo
Mariana [72]
Top right = B
bottom left = A
bottom right = C
4 0
3 years ago
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