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3 years ago

What do radio waves and gamma rays have in common?

Physics

2 answers:

Reil [10]3 years ago

7 0

Answer:

The only difference between radio waves, visible light and gamma rays is the energy of the photons.'

Bothrays have photons, but in radio waves they are weaker.

Andrews [41]3 years ago

3 0

Answer:

Radio waves and gamma rays have a common speed when they propagate in a vacuum. This speed is:

$3.10^{8} cm/s$

Explanation:

Gamma rays are produced naturally by atomic nuclei during their natural radiative transformations, and their wavelength is less than $10^{-12} m$ .

Such radiation has the property of ionizing atoms and also has great penetrating power. For its absorption, it is very common to use thick lead walls.

Radio waves are those with the lowest frequency and, consequently, the longest wavelengths, ranging from 10 m to 10 km. They are widely used in radio and TV broadcasts. These waves were generated for the first time by the German physicist Heinrich Rudolf Hertz, whose experiment was perfected, eight years later, by the Italian Guglielmo Marconi.

The speed of radio waves and river ranges in a vacuum is the same, this is something they have in common, their approximate value is: $3.10^{8} cm/s$

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Describe what happens, at a microscopic level, when an object is charged by rubbing. For instance, what happens when a plastic p

olga_2 [115]

Answer:

Explanation:

The static charges are generated due to excess or deficiency of electrons, because these are the smallest quanta of charge available at the molecular level which can get transferred with minimal energy requirement.

These charges are usually generated by friction between the two surfaces leading to the transfer of electron from one to another.

When a plastic pipe is rubbed with a cloth then due to friction the surface of the cloth loses electron which gets stuck at the surface of the pipe making it negatively charged.

7 0

3 years ago

A ball with a mass of 3kg is dropped from the top of a building this is 20m high. what is the velocity of the ball when it is 10

anzhelika [568]

Answer:

Velocity=14[m/s]

Explanation:

We can solve this problem by using the principle of energy conservation, where potential energy becomes kinetic energy.

In the attached image we can see the illustration of the ball falling from the height of 20 meters, at this time the potential energy will have the following value.

$Ep=m*g*h\\where:\\m=3[kg]\\h=20[m]\\$

$Ep=3*9.81*20\\Ep=588.6[J]$

When the ball passes through half of the distance (10m) its potential energy will have decreased by half as shown below.

$Ep=3*9.81*10\\Ep=294.3[m]$

If we know that potential energy is transformed into kinetic energy, we can find the value of speed.

$Ek=\frac{1}{2} *m*v^{2} \\therefore\\v=\sqrt{\frac{Ek*2}{m} } \\v=\sqrt{\frac{294.3*2}{3} } \\\\v=14[m/s]$

7 0

3 years ago

Jake drags a sled of mass 18 kg across the snow. The sled is attached to a rope that he pulls with a force of 70 N at an angle o

Advocard [28]

If the 30 N on the rope were pulled straight up, it would offset the force of gravity ( m g = 10 kg * 9.8 N/kg = 98 N) , leaving a net force up from the ground on the sled of 98-30 = 68 N. Since the rope is pulled at the angle of 25o, only part of the force is in the upward direction, (30N)(sin(25) = (30)(.423) = 12.7. So the net force becomes 98 N down offset by 12.7 up or 98-12.7 = 85.3 N. Ah, there it is: C.

8 0

3 years ago

Read 2 more answers

In the experiment, “Rolling Along”, which ball had the greater mass?

olga2289 [7]

Answer:

Explanation:

4 0

2 years ago

Determine the specific heat of a certain metal if a 450 gram sample of it loses 34 500 Joules of heat as its temperature starts

slamgirl [31]

Answer:

c = 0.4356 J/gK

Explanation:

Given the following data;

Mass = 450 grams

Initial temperature, T1 = 150°C

Final temperature, T2 = 53°C

Quantity of heat = 34500 Joules

To find the specific heat capacity of the metal;

Heat capacity is given by the formula;

$Q = mcdt$

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 53 - 150

dt = -97°C

Converting the temperature in Celsius to Kelvin, we have;

dt = 273 + (-97) = 176 Kelvin

Making c the subject of formula, we have;

$c = \frac {Q}{mdt}$

Substituting into the equation, we have;

$c = \frac {34500}{450*176}$

$c = \frac {34500}{79200}$

c = 0.4356 J/gK

6 0

3 years ago