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Amanda [17]
2 years ago
11

Which best describes cost-effectiveness

Physics
1 answer:
Rufina [12.5K]2 years ago
3 0

Answer:

Maintaining the lowest expenses for making a product.

Explanation:

Cost efficiency is the ability to use less resources (cost) to achieve greater output while cost effectiveness is the ability to use resources (cost) to achieve the objectives (outcomes).

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If the force exerted by a man is halved and the distance is multiplied by four, by which factor does the work change ?
jeyben [28]

increase factor by 8 thousands

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3 years ago
A constellation’s changing position in the sky, at the same time of the evening, over a period of several weeks is evidence that
Goryan [66]

Answer:

d- Earth revolves around the sun.

Explanation:

Earth rotation can be defined as the amount of time taken by planet earth to complete its spinning movement on its axis.

This ultimately implies that, the rotation of earth refers to the time taken by earth to rotate once on its axis. One spinning movement of the earth on its axis takes approximately 24 hours to complete with respect to the sun.

On the other hand, earth revolution can be defined as a complete trip along a path around the sun. This path is known as an orbit and it typically takes the Earth 365¼ days to complete it's journey around the Sun.

When a constellation (stars) changes its position in the sky, at the same time of the evening and over a period of several weeks; it ultimately implies or is an evidence that Earth revolves around the sun.

8 0
3 years ago
Can we see the back side of the moon from earth?
Olegator [25]

No. The moon always keeps the same side facing us. Its rotation and revolution periods are equal.

5 0
3 years ago
Read 2 more answers
What is meant by the motion of a force​
Vlad [161]

Answer:

Force is classified as a push or a pull

Explanation:

5 0
2 years ago
Use the Bohr model to address this question. When a hydrogen atom makes a transition from the 5 th energy level to the 2nd, coun
iris [78.8K]

Answer:

A. 2.82 eV

B. 439nm

C. 59.5 angstroms

Explanation:

A. To calculate the energy of the photon emitted you use the following formula:

E_{n1,n2}=-13.4(\frac{1}{n_2^2}-\frac{1}{n_1^2})     (1)

n1: final state = 5

n2: initial state = 2

Where the energy is electron volts. You replace the values of n1 and n2 in the equation (1):

E_{5,2}=-13.6(\frac{1}{5^2}-\frac{1}{2^2})=2.82eV

B. The energy of the emitted photon is given by the following formula:

E=h\frac{c}{\lambda}   (2)

h: Planck's constant = 6.62*10^{-34} kgm^2/s

c: speed of light = 3*10^8 m/s

λ: wavelength of the photon

You first convert the energy from eV to J:

2.82eV*\frac{1J}{6.242*10^{18}eV}=4.517*10^{-19}J

Next, you use the equation (2) and solve for λ:

\lambda=\frac{hc}{E}=\frac{(6.62*10^{-34} kg m^2/s)(3*10^8m/s)}{4.517*10^{-19}J}=4.39*10^{-7}m=439*10^{-9}m=439nm

C. The radius of the orbit is given by:

r_n=n^2a_o   (3)

where ao is the Bohr's radius = 2.380 Angstroms

You use the equation (3) with n=5:

r_5=5^2(2.380)=59.5

hence, the radius of the atom in its 5-th state is 59.5 anstrongs

8 0
3 years ago
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