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Charra [1.4K]
3 years ago
14

The air inside a bubble gum bubble is at atmospheric pressure. Imagine someone continuing to blow into that bubble. What happens

when the bubble’s volume is doubled?
Chemistry
1 answer:
solniwko [45]3 years ago
6 0

Answer: The correct answer is 'temperature will get doubled that is option D.

Explanation:

Suppose the volume of the bubble is V, at temperature T and Pressure exerted by atmosphere P.

When bubble is blown with more air until the volume doubles the initial volume:

The new volume of the bubble = V'=2V

The new Temperature of the air inside the bubble will change to T'.

And the atmospheric Pressure remains same.

According Charles law:

Volume\propto Temperature (At constant Pressure)

\frac{V_1}{T_2}=\frac{V_2}{T_2}

\frac{V}{T}=\frac{V'}{T'}

T'=\frac{2V\times T}{V}=2T

So, this means that temperature will get 2 times the initial temperature of the gas.

Hence, the correct answer is 'temperature will get doubled that is option D.

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Pablo drove 260 miles using 12 gallons of gas. at this rate, how many gallons of gas would he need to drive 286 miles?
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4 years ago
At what substrate concentration would an enzyme with a K_cat of 30.0 s⁻¹ and a Km of 0.0050 M operate at one-quarter of its maxi
Umnica [9.8K]

Answer:

The correct answer is option B.

Explanation:

Michaelis–Menten 's equation:

v=V_{max}\times \frac{[S]}{(K_m+[S])}=k_{cat}[E_o]\times \frac{[S]}{(K_m+[S])}

V_{max}=k_{cat}[E_o]

v = rate of formation of products

[S] = Concatenation of substrate = ?

[K_m] = Michaelis constant

V_{max}= Maximum rate achieved

k_{cat} = Catalytic rate of the system

E_o = initial concentration of enzyme

We have :

v=\frac{V_{max}}{4}

[S] =?

K_m=0.0050 M

v=V_{max}\times \frac{[S]}{(K_m+[S])}

\frac{V_{max}}{4}=V_{max}\times \frac{[S]}{(0.0050 M+[S])}

[S]=\frac{0.005 M}{3}=1.7\times 10^{-3} M

So, the correct answer is option B.

8 0
3 years ago
Why should you always condition a buret before running a titration?.
Alex Ar [27]

Answer:

Conditioning two or three times will insure that the concentration of titrant is not changed by a stray drop of water.

Explanation:

"Check the tip of the buret for an air bubble. To remove an air bubble, whack the side of the buret tip while solution is flowing".

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3 years ago
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