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Metals lose electrons under certain conditions to attain a noble gas electron configuration. How many electrons must be lost by

viva [34]

Answer:

2 electrons

E. neon

Explanation:

Metals lose electrons under certain conditions to attain a noble gas electron configuration. Magnesium has 12 electrons and its electron configuration is

1s² 2s² 2p6⁶ 3s²

When magnesium loses 2 electrons, it acquires the electron configuration of neon (10 electrons).

5 0

3 years ago

The cell potential of a redox reaction occurring in an electrochemical cell under any set of temperature and concentration condi

avanturin [10]

Answer : The actual cell potential of the cell is 0.47 V

Explanation:

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given redox reaction is :

$Ni^{2+}(aq)+Zn(s)\rightarrow Ni(s)+Zn^{2+}(aq)$

The balanced two-half reactions will be,

Oxidation half reaction : $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction : $Ni^{2+}+2e^-\rightarrow Ni$

The expression for reaction quotient will be :

$Q=\frac{[Zn^{2+}]}{[Ni^{2+}]}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q=\frac{(0.0141)}{(0.00104)}=13.6$

The value of the reaction quotient, Q, for the cell is, 13.6

Now we have to calculate the actual cell potential of the cell.

Using Nernst equation :

$E_{cell}=E^o_{cell}-\frac{RT}{nF}\ln Q$

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = 316 K

n = number of electrons in oxidation-reduction reaction = 2 mole

$E^o_{cell}$ = standard electrode potential of the cell = 0.51 V

$E_{cell}$ = actual cell potential of the cell = ?

Q = reaction quotient = 13.6

Now put all the given values in the above equation, we get:

$E_{cell}=0.51-\frac{(8.314)\times (316)}{2\times 96500}\ln (13.6)$

$E_{cell}=0.47V$

Therefore, the actual cell potential of the cell is 0.47 V

4 0

3 years ago

HELP ASAP PLEASE PLEASE PLEASE Complete and balance the following reaction. Note that Cr forms +3 in the product. ____ Sn(NO3)2

Rzqust [24]

Answer:

Explanation:

3Sn(NO3)2 (aq) + 2Cr(s) → 2Cr(NO3)3(aq ) + 3Sn(S )

5 0

3 years ago

If the same amount of heat is added to 5.00 g samples of each of the metals below, which metal will experience the smallest temp

Y_Kistochka [10]

Answer: -

Lower the specific heat capacity of the metal, more the amount of heat would be required to raise the temperature to the same extent.

So for the same amount of heat added to 5.00 g samples of metals, the metal with the lowest specific heat capacity would experience the smallest temperature change.

For example, if the elements are Al, Au ,Cu and Fe, then Au would experience the smallest temperature change due to least specific heat capacity.

5 0

3 years ago

In the chemical equation 2Mg(s) + O2(g) ? 2MgO(s),

cluponka [151]

The correct answer is D

4 0

3 years ago