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lord [1]
3 years ago
11

Type the correct answer in each box.

Chemistry
1 answer:
BARSIC [14]3 years ago
4 0

Answer:

mg3n2 and cacl3 hope it helps

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Describe the properties of alkali metals. based on their electronic arrangement, explain whether they exist alone in nature.
saul85 [17]

The alkali metals can't exist alone in nature because of incomplete outermost shell of alkali metals.

<h3>What are the  properties of alkali metals?</h3>

The alkali metals have the high thermal and electrical conductivity. It has high lustre, ductility, and malleability as compared to other materials. Each alkali metal atom has one electron in its outermost shell which make more reactive.

So we can conclude that the alkali metals can't exist alone in nature because of incomplete outermost shell of alkali metals.

Learn more about metal here: brainly.com/question/25597694

#SPJ1

5 0
2 years ago
Use the word bank to complete the charts about the metrics system measurement
Aloiza [94]

Answer:

Length

- centimetre

- millimetre

- kilometre

- meter

Mass

- gram

- kilogram

Capacity

- liter

- millilitre

I don't know why mass is there but hope this helps! :)

5 0
3 years ago
How many molecules of copper sulfate are needed to produce 5.0×1024 molecules of sodium sulfate?
lubasha [3.4K]

Answer:

5.0 × 10²⁴ molecules

Explanation:

Step 1: Write the balanced double displacement reaction

2 NaOH + CuSO₄ ⇒ Na₂SO₄ + Cu(OH)₂

Step 2: Calculate the moles corresponding to 5.0 × 10²⁴ molecules of Na₂SO₄

We will use Avogadro's number: there are 6.02 × 10²³ molecules in 1 mole of molecules.

5.0 × 10²⁴ molecule × 1 mol/6.02 × 10²³ molecule = 8.3 mol

Step 3: Calculate the moles of CuSO₄ required to produce 8.3 moles of Na₂SO₄

The molar ratio of CuSO₄ to Na₂SO₄ is 1:1. The moles of CuSO₄ required are 1/1 × 8.3 mol = 8.3 mol.

Step 4: Calculate the molecules corresponding to 8.3 moles of CuSO₄

We will use Avogadro's number.

8.3 mol × 6.02 × 10²³ molecule/1 mol = 5.0 × 10²⁴ molecule

4 0
3 years ago
During the combustion of methane (CH4), one mole of methane gas combines with two moles of oxygen gas (O2) to produce one mole o
astraxan [27]

Answer:

CH4(g) +2O2____ CO2(g) +2H2O (l)

3 0
3 years ago
Find the number of moles of water that can be formed if you have 138 mol of hydrogen gas and 64 mol of oxygen gas.
charle [14.2K]
2H₂₍g₎ + O₂ ₍g₎→ 2H₂O

138 mol H₂ × (2 mol H₂O ÷ 2 mol H₂)= 138 mol H₂O
64 mol O₂ × (2 mol H₂O ÷ 1 mol O₂)= 128 mol H₂O

128 mol H₂O
6 0
3 years ago
Read 2 more answers
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