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34kurt
4 years ago
13

Which of these elements in group 1A has the largest atomic radius? Cesium, Rubidium, Potassium, or Sodium?

Chemistry
2 answers:
Savatey [412]4 years ago
8 0
Cesium is the element in group 1A that has the largest atomic radius, with the number of 225.
Rubidium has 211, Potassium 196, and Sodium 154.
Reika [66]4 years ago
4 0

Answer: Option (a) is the correct answer.

Explanation:

It is known that when we move down a group then there occurs an increase in the size elements due to the addition of more number of electrons into new shells.

Hence, it means that atomic radius of the elements also increases.

For the given group 1A elements, sodium is at the top so it has smaller atomic radius whereas cesium is at the bottom. Therefore, cesium has the largest atomic radius.

Thus, we can conclude that cesium elements in group 1A has the largest atomic radius.

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For the following reaction, 25.4 grams of sulfur dioxide are allowed to react with 11.6 grams of water . sulfur dioxide(g) water
Gekata [30.6K]

Answer:

The maximum mass of sulfurous acid that can be formed is 32.54 grams.

Explanation:

The balanced reaction is:

SO₂ + H₂O → H₂SO₃

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • SO₂: 1 mole
  • H₂O: 1 mole
  • H₂SO3: 1 mole

Being the molar masses of each compound:

  • SO₂: 64 g/mole
  • H₂O: 18 g/mole
  • H₂SO₃: 82 g/mole

Then, by stoichiometry the following quantities of mass participate in the reaction:

  • SO₂: 1 mole* 64 g/mole= 64 g
  • H₂O: 1 mole* 18 g/mole= 18 g
  • H₂SO₃: 1 mole* 82 g/mole=82 g

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, you can use a simple rule of three as follows: If 18 grams of water react with 64 grams of sulfur dioxide, how much mass of sulfur dioxide does 11.6 grams of water react with?

mass of sulfur dioxide=\frac{11.6 grams of water*64 grams of sulfur dioxide}{18 grams of water}

mass of sulfur dioxide= 41.24 grams

But 41.24 grams of sulfur dioxide are not available, 25.4 grams are available. Since you have less mass than you need to react with 11.6 grams of water, sulfur dioxide will be the limiting reagent.

Then you can apply the following rule of three: if by reaction stoichiometry 64 grams of sulfur dioxide produce 82 grams of sulfurous acid, 25.4 grams of sulfur dioxide, how much mass of sulfurous acid will it produce?

mass of sulfurous acid=\frac{25.4 grams of sulfur doixide*82 grams of sulfurous acid}{64 grams of sulfur doixide}

mass of sulfurous acid= 32.54 grams

<u><em>The maximum mass of sulfurous acid that can be formed is 32.54 grams.</em></u>

<u><em></em></u>

7 0
3 years ago
Hi people senko-San is best wifu change my mind
fenix001 [56]

Answer:dude what are you doing here?

Explanation:also i don’t know if I can lol

5 0
3 years ago
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A certain substance x decomposes. it is found that 50% of x remains after 100 minutes. how much x remains after 200 minutes if t
fiasKO [112]
The time needed for a substance becomes half of it mass is called half-time, after. In this case, the half time is 100 minutes. Then to know how much substance remain after 200 minutes the equation would be:

Substance remains= 1/2^(time/half-time) x substance initial mass
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What is the mass of an atom with seven protons, seven neutrons, and seven electrons? Record and bubble in your answer below.
Irina-Kira [14]

Answer:

Mass would be 14 amu

Explanation:

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