It’s 77 so we don’t know how about it is
To add or sum this arrary, beg ∈ {array} {r} 37 \202\ + 160/ ∈ end {array} gives <u>A) 399</u>.
<h3>What is an array?</h3>
An array is a data structure made up of some elements.
The sum of all elements in an array is found by adding up the elements in the array.
<h3>Data and Calculations:</h3>
Elements of the array = 37, 202, and 160
The sum of the array, 37 + 202 + 160 = 399
Thus, to add or sum this arrary, beg ∈ {array} {r} 37 \202\ + 160/ ∈ end {array} gives <u>A) 399</u>.
Learn more about arrays at brainly.com/question/23698059
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<h3>Question:</h3>
Add beg ∈ {array} {r} 37 \202\ + 160/ ∈ end {array}
<h3>Answer Options:</h3>
A) 399
B) 389
C) 400
D) 409
Answer:
<h3>A. </h3>

- log
= log 3 - x³ log x = log 3
- 3x³ log x = 3 log 3
- x³ log x³ = log 3³
= 3³- x³ = 3
- x =

<h3>B.</h3>
- 4ˣ + 6ˣ = 9ˣ
- 2²ˣ + 2ˣ3ˣ = 3²ˣ
<u>Divide both sides by 2²ˣ</u>
<u>Substitute (3/2)ˣ = t</u>
<u>Solve for t:</u>
<u>Positive root is considered as (3/2)ˣ can't be negative.</u>
- (3/2)ˣ = (1 + √5)/2
- x = log [(1 + √5)/2] / log (3/2)
- x = 1.18681439028
Answer:
heyyy
Step-by-step explanation:
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Answer:
13
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean Theorem

where<em> a</em> and <em>b</em> are the legs and <em>c</em> is the hypotenuse.
We know that the legs are 5 and 12. We also know the hypotenuse is x, or unknown.
Substitute 5 in for <em>a</em>, 12 for <em>b, </em>and x for <em>c.</em>
<em />
<em />
Evaluate the exponents.
5^2 is the same as 5*5, which is 25.
12^2 is the same as 12*12, which is 144.

Add 25 and 144

We are trying to find out what <em>x</em> is. In order to do this, we have to get <em>x</em> alone. Since x is being squared, take the square root of both sides. The exponent and square root will cancel, leaving x by itself.

The hypotenuse is 13.