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artcher [175]
3 years ago
15

Batching s father is 26 years younger than Batching s grand father and 29 years older than Baching.The sum of the ages of all th

e three is 135 years.What is the age of each of them?
Mathematics
2 answers:
Shalnov [3]3 years ago
7 0

x + (x + 29) + (x + 26 + 29) = 135
3x + 84 = 135
3x = 51
x = 17

Baching is 17 his father is 46 and grandfather is 72
kolbaska11 [484]3 years ago
7 0

We can create some equations with this

Let f = Batching's father's age

Let g = Batching's Grandfather's age

Let b = Batching's age

f = g - 26

f = b + 29

f + g + b = 135


To solve this, plugin the solution for one equation into another

f + 26 = g

f - 29 = b

f + f + 26 + f - 29 = 135

3f - 3 = 135

3f = 138

f = 46

Now that we have the fathers age, we can get the other's age

46 = g - 26

46 = b + 29

meaning that f = 72

and b = 17

Batching's father's age = 46

Batching's Grandfather's age = 72

Batching's age = 17

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(1) 0.5933

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 P(F) = 0.69

Probability that bags entering the building does not contains forbidden material,   P(NF) = 1 - 0.69 = 0.31

Let event A = alarm gets triggered

Probability that alarm gets trigger given the bags contain forbidden material, P(A/F) = 0.77

Probability that alarm gets trigger given the bags does not contain forbidden material, P(A/NF) = 0.20

(1) Probability that a bag triggers the alarm, P(A) ;

         P(A) = P(F) * P(A/F) + P(NF) * P(A/NF)

                 = (0.69 * 0.77) + (0.31 * 0.20) = 0.5313 + 0.062

                 = 0.5933

Therefore, probability that a bag triggers the alarm is 0.5933 .

(2) Probability that a bag that triggers the alarm will actually contain forbidden material is given by P(F/A) ;

Using Bayes' Theorem;

    P(F/A) = \frac{P(F) * P(A/F)}{P(F) * P(A/F) + P(NF) *P(A/NF)} = \frac{0.69*0.77}{0.69*0.77+0.31*0.20} = \frac{0.5313}{0.5933}

               = 0.8955

6 0
3 years ago
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