Please solve all of these, 50 points and I will be marking it brainliest, no links, they will be reported.

HEYOO PEEPS Find the scale factor.

valentina_108 [34]

Answer:

I think it is 9

Step-by-step explanation:

as for number one I did 5×7=35 overall and 15×21= 315

then I did 315÷35=9 which is the scale factor.

hope this is correct and help u understand:)

7 0

3 years ago

Read 2 more answers

Which value is a part of the domain? <br> -2.7<br> -2.2<br> -1.9

ozzi

Answer:

hmm, i think is -2.2 if am correct.

Step-by-step explanation:

7 0

2 years ago

Select the point that is a solution to the system of inequalities.<br> y≤2x-2<br> y≤ x²-3x

miss Akunina [59]

Both statements are true. Therefore (4,2) is a solution and option D is correct.

The given inequalities are $y\leq 2x-2$ and $y\leq x^{2} -3x$ .

We need to select the point that is a solution to the system of inequalities (-2,-1), (1,3), (2,1) and (4,2).

<h3>What is an example of a system of inequalities in real life?</h3>

Inequalities can be seen in the speed limits on roads, the minimum age for seeing certain movies, and the distance you have to walk to go to the park. Inequalities represent a limit of what is permitted or achievable rather than a precise quantity.

Any point is a solution to this system of inequality if it satisfies both inequalities.

Check the inequalities by each option.

For (-2, -1), $-1\leq 2(-2)-2 \implies -1\leq -6$ .

This statement is false because -1 is greater than -6. Therefore (-2,-1) is not a solution and option A is incorrect.

For (1, 3), $3\leq 2(1)-2 \implies 3\leq 0$

This statement is false because 3 is greater than 0. Therefore (1,3) is not a solution and option B is incorrect.

For (2,1), $1\leq 2(2)-2 \implies 1\leq 2$ .

$1\leq 2^{2} -3(2) \implies 1\leq -2$

This statement is false because 1 is greater than -2. Therefore (2,1) is not a solution and option C is incorrect.

For (4,2), $2\leq 2(4)-2 \implies 2\leq 6$

$2\leq 4^{2} -3(4) \implies 2\leq 4$

Both statements are true. Therefore (4,2) is a solution and option D is correct.

To learn more about inequalities visit:

brainly.com/question/20383699.

#SPJ1

7 0

2 years ago

For the equation |ax+b|=c (where a,b, and c are real numbers and a≠0), what value of c results in exactly one solution?

Degger [83]

Step-by-step explanation:

Correct option is

D

a



=0,b



=0

The condition for ax+by+c=0 to be a linear eqaution in two variables is

a



=0,b



=0

7 0

2 years ago

An assembly consists of two mechanical components. Suppose that the probabilities that the first and second components meet spec

harkovskaia [24]

Answer:

P(X = 0) = 0.0208, P(X = 1) = 0.2484, P(X = 2) = 0.7308

Step-by-step explanation:

Let's define the following events

A: the first component meet specification

B: the second component meet specification

P(A) = 0.87

P(B) = 0.84

Let X be the random variable that represents the number of components in the assembly that meet specifications. Because there are only two mechanical components in the assembly, X can only take the values 0, 1, 2.

P(X = 0) = P(the first component does not meet specification and the second component does not meet specification) =

$P(A^{c}\cap B^{c}) = P(A^{c})P(B^{c})$ (because of independence)

= (0.13)(0.16) = 0.0208

P(X = 1) = P(only one component meet specification) = P[(the first component meet specification and the second component does not meet specification) or (the first component does not meet specification and the second component meet specification)] =

$P[(A\cap B^{c})\cup (A^{c}\cap B)] = P(A\cap B^{c}) + P(A^{c}\cap B)=$ (because sets are mutually exclusive)

$P(A)P(B^{c}) + P(A^{c})P(B)=$ (because of independence)

= (0.87)(0.16) + (0.13)(0.84) = 0.2484

P(X = 2) = P(both components meet specifications) =

$P(A\cap B) = P(A)P(B)$ (because of independence)

= (0.87)(0.84)

= 0.7308

8 0

3 years ago

Please solve all of these, 50 points and I will be marking it brainliest, no links, they will be reported.​

Please solve all of these, 50 points and I will be marking it brainliest, no links, they will be reported.