Middle option.
<span>(x + 1 ≤ 1) ∩ (x + 1 ≥ 1)
If you work both sides separately you get
</span>(x ≤ 0) ∩ (x ≥ 0)
<span>
which reduces nicely to
</span><span>{x | x = 0}</span>
Hey there I see you need help well that's why I am here for a square the one side could be 6 or for a rectangle the l vould be 6 and the W could be 4 or 8 and 3 or lastly 12 and 2 hope this helps
Answer:
The answer is B.
Step-by-step explanation:
