|x| = x for x ≥ 0
examples:
|3| = 3; |0.56| = 0.56; |102| = 102
|x| = -x for x < 0
examples:
|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102
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Use PEMDAS:
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
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Put the values of x to the equation of the function h(x):
6/x=27
times both sides by x
6=27x
divide both sides by 27
6/27=x
2/9=x
the missing number is 2/9
{-1, 5, 11, 17, 23} ................
you can make it into an improper fraction if you want but there is no need for this problem
steps
1) 10 3/4- 5 1/4
10-5=5
3/4-1/4=2/4 or 1/2
answer:5 1/2 or 5 2/4
(it is better simplified)
5x-9y=-65
10x-3y=20
Multiple the first equation by 2
10x-18y=-130
10x -3y=20
Then subtract the two equations to get rid of the x
21y=-150
Divide the -150 by 21
Y=-7.14
Plug the y into the original equation. (Either one)
5x-9(-7.14)=-65
5x-64.28=-65
Then add 64.28 to the -65
5x=-0.72
Divide by 5
X=-0.144
I hope this is right
