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xxTIMURxx [149]
3 years ago
13

Which set of side lengths forms a right triangle? A) 5 cm, 6 cm,7 cm B) 2 cm, 4 cm, 6 cm C) 8 cm, 9 cm, 11 cm D) 8 cm, 15 cm, 17

cm​
Mathematics
1 answer:
Tamiku [17]3 years ago
3 0
A) 5cm,6cm,7cm
you’re welcome
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What is the surface area of a rectangular prisim with dimensions 5ft, 6ft, and 7ft.
djyliett [7]

Ok the formula for this is 2(lw +hw+hL)

2(30+35+42)=2(107)=214 square feet

8 0
3 years ago
Read 2 more answers
A triangular bandana has an area of 46 square inches. The height of the triangle is 5 3 4 inches. Enter and solve an equation to
shutvik [7]

Answer: 16 inches

Step-by-step explanation:

The area of a triangle = bh/2

where b = base = unknown

h = height = 5 3/4 inches

Area = 46 inches²

Therefore, 46 = base × 5 3/4 / 2

Cross multiply

46 × 2 = base × 5 3/4

92 = base × 5 3/4

Base = 92 ÷ 5 3/4

Base = 92 ÷ 23/4

Base = 92 × 4/23

Base = 4 × 4

Base = 16 inches

8 0
3 years ago
PLEASE HELP ME WITH THIS
Vedmedyk [2.9K]
Let's start with the drawing. (See the drawing at the bottom of this answer.)

Draw a vertical segment.
At the bottom endpoint, draw a horizontal segment to the right.
The angle at the bottom left is a right angle.
So far this should look like an "L" shape.
The vertical segment is the wall, and the horizontal segment is the ground.

Now draw a segment that connects the right endpoint of the horizontal segment and the top endpoint of the vertical segment. Now you have a right triangle. The diagonal segment represents the ladder. The diagonal segment is the hypotenuse. Label the diagonal segment, the hypotenuse, 12 ft.
Label the vertical segment, the wall, 11.8 ft.

The angle at the bottom right is A. It is the angle the ladder makes with the ground. This angle cannot be greater than 75 degrees.

Now we use trigonometry to find the measure of angle A.

For this right triangle, and its angle A, you have a hypotenuse that measures 12 ft, and an opposite leg that measures 11.8 ft.
We need to find angle A.
The trig ratio that relates the opposite leg and the hypotenuse is the sine.

\sin A = \dfrac{opp}{hyp}

\sin A = \dfrac{11.8}{12}

\sin A = 0.98333

Since the sine of angle A equals 0.98333, we use the inverse sine function to find the measure of angle A.

A = \sin^{-1} 0.98333

A = 79.5^\circ

Answer:
The angle the ladder makes with the ground is 79.5 degrees which is greater than 75 degrees, so the ladder it will be unsafe in this position.


           |\
           |  \
           |    \
           |      \
opp = |         \ hyp = 12
= 11.8  |           \
           |             \
           |_______\  A
3 0
3 years ago
Consider the following linear equation.y = -1-Step 1 of 2: Determine the slope and the y-intercept (entered as an ordered pair)
Dmitriy789 [7]

Recall that a slope-intercept form of a linear equation is

\begin{gathered} y=mx+b \\ \text{where} \\ m\text{ is the slope} \\ b\text{ is the y-intercept} \end{gathered}

Rearrange the given so that it follows that slope intercept form

\begin{gathered} y=-1-\frac{2}{5}x\Longrightarrow y=-\frac{2}{5}x-1 \\  \\ \text{Now that it is in the slope intercept form} \\ y=-\frac{2}{5}x-1 \\ \text{we can determine that the slope is } \\ m=-\frac{2}{5} \\ \text{and the y-intercept is} \\ b=-1 \end{gathered}

The y-intercept is the value for which the linear function crosses the y-axis, this is when the value of x is equal to zero. The ordered pair therefore of the y-intercept is (0,-1).

8 0
1 year ago
David is filling out orders for an online business and gets paid $1 for each order he fills out plus bonus of 25 cents per order
svp [43]

Answer:

David will make $481 (he earns the bonus)

Explanation:

<em>If he makes $1 for each order and he filled out 385 orders, then why can't we say he made $385?</em>

Because of this statement rights here:

"...and gets paid $1 for each order he fills out plus bonus of 25 cents per order if the average number of orders he completes per day within any of the given weeks exceeds 20."

So we need to find out if any of the 3 weeks has an average of 20+ orders per day.

<h2>David is filling out orders for an online business and gets paid $1 for each order he fills out</h2>

(x is the amount of orders he fills out)

profit = $1x

<h2>plus bonus of 25 cents per order if the average number of orders he completes per day within any of the given weeks exceeds 20. </h2>

if any average orders per day is > 20 in any week

bonus profit = $1.25x

<h2>The ratio of the number of orders he processed during the first week to the number of orders he processed during the second week is 3:2, </h2>

first week     second week

             3a : 2a

<h2>while the the ratio that compares the number of orders he filled out during the first and the third weeks is 4 to 5 respectively. </h2>

first week   third week

           4a : 5a

<h2>What amount of money will David make at the end of three weeks if the total number of orders he filled out was 385?</h2>

sum of all ratios of a = 385

So we have

3a : <u>2a</u> (first week to <u>second week</u>)

4a : <em>5a </em>(first week to <em>third week</em>)

Notice how the first two numbers are both from the first week. Let's use the Least Common Multiple to make them equal while still keeping ratios.

LCM of 3 and 4: 12 = 3 * 4

12a : <u>8a</u> ( times 4 )

12a : <em>15a</em> ( times 3 )

Now that we have the same value, we can create a big ratio

first week <u>second week</u> <em>third week</em>

   12a     :        <u>8a</u>          :      <em>15a</em>

we know that these ratios will all equal 385. Since ratios are equal no matter how big we make them, we can say that

12a + <u>8</u>a + <em>15</em>a = 385 (a is a variable to scale up the ratio)

which is the same as

(12 + <u>8</u> + <em>15</em>) * a = 385

(<em><u>35</u></em>) * a = 385

35a = 385

if we solve for a by dividing 35 on both sides we get

a = 11

This gives us how much to multiply the RATIO by to get the ACTUAL NUMBER of orders completed. Let's plug 11 for 'a' and see what happens.

12a + <u>8</u>a + <em>15</em>a = 385

12(11) + <u>8</u>(11) + <em>15</em>(11) = 385

132 + <u>88</u> + <em>165</em> = 385     (Check that out, the number of orders each week!)

<u>220</u> + <em>165</em> = 385

<em><u>385</u></em> = 385

Bingo! All the math works out. So, looking back at the verryyy top of this problem, the reason why it wasn't as easy as $385 was because of the bonus.

The bonus gives David $1.25 per order instead of $1 per order if any of the weeks have an average ORDER PER DAY of anything bigger than 20. If we know the real numbers of orders for every week (132, <u>88</u>, and <em>165</em>), then we can divide it by 7 to get the average order per day. Let's choose <em>165 </em>(the <em>third week</em>) because it is the biggest and has the greatest chance of meeting our goal.

165 orders / 7 days (7 days in a week) = 23.57 orders per day

Is this greater than 20 orders per day?

YES!

So now we can safely say that the bonus is there or not, and in this case, the bonus IS there because there is a week where David had more than 20 orders per day.

So instead of using

profit = $1x

We will use

bonus profit = $1.25x

(x is the amount of orders completed)

So if we know he completed 385 orders, and we know he earned the bonus, we plug in 385 for x for the bonus function

bonus profit = $1.25x

bonus profit = $1.25 * 385

bonus profit = $481.25

If necessary, round your answer to the nearest dollar.

So for the very end, all we have to do is round it to the nearest dollar.

$481.25 rounds to $481.

And we're done!

8 0
3 years ago
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