Given the table below, evaluate the following:
1 answer:
Part A
See the image labeled "part A". We'll use the values marked in blue and red for f(2) and g(2) respectively. These values are the function outputs when the input is x = 2.
(f-2g)(x) = f(x) - 2*g(x)
(f-2g)(2) = f(2) - 2*g(2)
(f-2g)(2) = 1 - 2*3
(f-2g)(2) = -5
Answer: -5
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Part B
See the image labeled "part B". We'll use the values marked in blue and red for g(-1) and f(0) respectively.
We have to start with g(-1) and then chain it to finding f(0) afterward.
g(-1) = 0
f(g(-1)) = f(0) = 9
Answer: 9
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Part C
See the image labeled "part C". We'll use the values marked in blue and red for g(-2) and g(-3) respectively.
Because g(-2) is the innermost function, it must go first, then g(-3) can go next.
g(-2) = -3
g(g(-2)) = g(-3) = 8
Answer: 8
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Answer:
The graph of g is 3 units above the graph of f.
Step-by-step explanation:
Adding 3 to each y-value shifts the graph up 3 units.
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In the case of the straight line given here, it also has the appearance of shifting the graph left. The left-shift, however, is not 3 units. The amount of apparent horizontal shift will depend on the slope of the original line.
