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mamaluj [8]
4 years ago
12

Explain why Newton's laws of motion do not hold true in a non-inertial frame of reference

Physics
1 answer:
zaharov [31]4 years ago
7 0

Explanation:

b'coz of the air we make it in the earth

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A yet-to-be-built spacecraft starts from Earth moving at constant speed to the yet-tobe-discovered planet Retah, which is 20 lig
Gre4nikov [31]

Answer:

The  time elapsed at the spacecraft’s frame is less that the time elapsed at earth's  frame

Explanation:

From the question we are told that

The distance between earth and Retah is  d = 20 \ light \ hours =  20 * 3600 *  c =  72000c \ m

Here c is the peed of light with value c =  3.0*10^8 m/s

The time taken to reach Retah from earth is  t =  25 \ hours  =  25 * 3600 =90000 \ sec

The velocity of the spacecraft is mathematically evaluated  as

     v_s =  \frac{d }{t}

substituting values

   v_s =  \frac{72000 * 3.0*10^{8} }{90000}

    v_s =  2.40*10^{8} \ m/s

The time elapsed in the spacecraft’s frame is mathematically evaluated as

      T  =  t *  \sqrt{ 1 -  \frac{v^2}{c^2} }

substituting value

       T  =  90000 *  \sqrt{ 1 -  \frac{[2.4*10^{8}]^2}{[3.0*10^{8}]^2} }

        T = 54000 \ s

=>    T  = 15 \ hours

So  The  time elapsed at the spacecraft’s frame is less that the time elapsed at earth's  frame

       

7 0
3 years ago
Why is the coefficient of friction independent of the mass?
Svet_ta [14]
Because the coefficient of friction depends on the surface
3 0
4 years ago
The water was used to power a generator, creating _______________ energy
Nikitich [7]

Answer:

electric

<em>please give brainliest</em>

3 0
2 years ago
A bob of mass of 0.18 kilograms is released from a height of 45 meters above the ground level. What is the value of the kinetic
il63 [147K]
I think the best answer is b 
4 0
4 years ago
Read 2 more answers
A block of mass m1 = 290 g is at rest on a plane that makes an angle θ = 30° above the horizontal. The coefficient of kinetic fr
GrogVix [38]

Answer:

The speed of the block when is fallen 30cm

v=0.726\frac{m}{s}

Explanation:

∑F= (m2)g - ƒ - (m1)g*sin(θ) = (m1)a

g = 9.81 m/s²

ƒ  = μN = μ(m1)g

(m2)*g - u*(m1)*g - (m1)*g*sin(\alpha ) = (m1)*a

(0.200)(9.81) - (0.1)(0.290)(9.81) - (0.290)(9.81)sin(30°) = (0.290)a

(0.200kg)(9.81\frac{m}{s^{2}}) - (0.1)(0.290kg)(9.81\frac{m}{s^{2}}) - (0.290kg)(9.81\frac{m}{s^{2}})sin(30°) = (0.290kg)*a

0.511101=0.29*a\\a=0.879\frac{m}{s^{2} }

v_{f}^{2}=v_{o}^{2}+2*a(x_{f}^{2}-v_{o}^{2})\\v_{o}=0\\v_{o}=0\\v_{f}^{2}=2*a(x_{f})\\v_{f}=\sqrt{2*a(x_{f})}\\v_{f}=\sqrt{2*0.879\frac{m}{s^{2}}*0.30m} \\v_{f}=0.726 \frac{m}{s}

5 0
4 years ago
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