Ask question

Ask question

All categories

4 years ago

9

What are some examples of irreversible processes in nature?

1 answer:

castortr0y [4]4 years ago

8 0

Answer:

Burning. When you burn something, it turns into ash you can't make that thing turn into what it was before.

You might be interested in

is it possible for the gravitational force between two 50-kg objects to be less than the gravitational force between a 59-kg obj

Eva8 [605]

OF COURSE !

The gravitational force between two objects doesn't ONLY depend on the product of their masses. It also depends on the distance between them.

I'm not even going to work out the numbers for my example. I'm just going to state without proof that at the top of the 2nd frame, the gravitational force between you and your bowling ball is greater than the gravitational force between you and the whole darn Andromeda galaxy ! My reasoning is based on the fact that your bowling ball is maybe 1 foot from your center of mass, whereas the Andromeda galaxy is more like 2.5 million light years from it. That right there is going to give your bowling ball a big advantage when it comes to gravity !

5 0

3 years ago

kiruha [24]

Answer:

Explanation:

3 0

3 years ago

Heyyyy! can some tell me if im right?

White raven [17]

Answer:

no the answers r b, d, r, and f

Explanation:

5 0

3 years ago

Read 2 more answers

A two-turn circular wire loop of radius 0.63 m lies in a plane perpendicular to a uniform magnetic field of magnitude 0.219 T. I

Basile [38]

Answer:

The magnitude of the average induced emf in the wire during this time is 9.533 V.

Explanation:

Given that,

Radius r= 0.63 m

Magnetic field B= 0.219 T

Time t= 0.0572 s

We need to calculate the average induce emf in the wire during this time

Using formula of induce emf

$E=-\dfrac{d\phi}{dt}$

$E=-B\dfrac{dA}{dt}$

$E=-B\dfrac{A_{2}-A_{1}}{dt}$

$E=B\dfrac{A_{1}-A_{2}}{dt}$ .....(I)

In reshaping of wire, circumstance must remain same.

We calculate the length when wire is in two loops

$l=2\times 2\pi\times r_{1}$

$l=2\times 2\pi\times 0.63$

$l=7.916\ m$

The length when wire is in one loop

$l=2\pi\times r_{2}$

$7.916=2\times \pi\times r_{2}$

$r_{2}=\dfrac{7.916}{2\times \pi}$

$r_{2}=1.259\ m$

We need to calculate the initial area

$A_{1}=N\times\pi\times r_{1}^2$

Put the value into the formula

$A_{1}=2\times3.14\times(0.63)^2$

$A_{1}=2.49\ m^2$

The final area is

$A_{2}=N\times\pi\times r_{2}^2$

$A_{2}=1\times\pi\times(1.259)^2$

$A_{2}=4.98\ m^2$

Put the value of initial area and final area in the equation (I)

$E=0.219\dfrac{2.49-4.98}{0.0572}$

$E=-9.533\ V$

Negative sign shows the direction of induced emf.

Hence, The magnitude of the average induced emf in the wire during this time is 9.533 V.

6 0

3 years ago

A simple arrangement by means of which e.m.f,s. are compared is known

strojnjashka [21]

Answer:

A simple arrangement by means of which e.m.f,s. are compared is known as?

(a)Voltmeter

(b)Potentiometer

(c)Ammeter

(d)None of the above

Explanation:

5 0

3 years ago