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3 years ago

What dating technique could scientists use to find the age of a meteorite?

Physics

1 answer:

kvasek [131]3 years ago

8 0

Radiometric dating?
Also, possibly radiocarbon dating

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Ist Law: a object continues in a state of

ArbitrLikvidat [17]

Answer:

Explanation:

This image is the example of Newton's first law of motion because:

As per Newton's first law, football will remain in the state of rest until a player applies an external force by kicking the ball.

And the ball will keep on moving until unless the net of a goal post exerts the external force to stop the ball.

6 0

3 years ago

When you kick a ball by a force of 26.3 newtons, what is the magnitude and direction of the force that you experience?

VikaD [51]

26.3 N in the reverse direction

6 0

3 years ago

Which are the simplest pure substances that cannot be broken down into any other substances

Veseljchak [2.6K]

The simplest pure substances that cannot be broken down into any other substances are elements, such as gold (Au) or oxygen (O).

6 0

3 years ago

Most automobiles have a coolant reservoir to catch radiator fluid that may overflow when the engine is hot. A radiator is made o

Colt1911 [192]

Answer:

There is a loss of fluid in the container of 0.475L

Explanation:

To solve the problem it is necessary to take into account the concepts related to the change of voumen in a substance depending on the temperature.

The formula that describes this thermal expansion process is given by:

$\Delta V = \beta V_0 \Delta T$

Where,

$\Delta V =$ Change in volume

$V_0 =$ Initial Volume

$\Delta T =$ Change in temperature

$\beta =$ coefficient of volume expansion (Coefficient of copper and of the liquid for this case)

There are two types of materials in the container, liquid and copper, so we have to change the amount of Total Volume that would be subject to,

$\Delta V_T = \Delta V_l - \Delta V_c$

Where,

$\Delta V_l$ = Change in the volume of liquid

$\Delta V_c$ = Change in the volume of copper

Then replacing with the previous equation we have:

$\Delta V = \beta_l V_0 \Delta T- \beta_c V_0 \Delta T$

$\Delta V = (\beta_l-\beta_c)V_0\Delta T$

Our values are given as,

Thermal expansion coefficient for copper and the liquid to 20°C is

$\beta_c = 51*10^{-6}/\°C$

$\beta_l = 400*10^{-6}/\°C$

$V_0 = 16L$

$\Delta T = (95\°C-10\°C)$

Replacing we have that,

$\Delta V = (\beta_l-\beta_c)V_0\Delta T$

$\Delta V = (400*10^{-6}/\°C-51*10^{-6}/\°C)(16L)(95\°C-10\°C)$

$\Delta V = 0.475L$

Therefore there is a loss of fluid in the container of 0.475L

6 0

3 years ago

What is the distance traversed by the particle between 0 seconds and 6 seconds?

ad-work [718]

Answer:

I dont know to be honest

Explanation:

i dont know to be honest

5 0

3 years ago