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mojhsa [17]
3 years ago
6

You go to a basketball game and buy 3 Waters that cost X dollars each and a bag of peanuts for $4.50. write an expression in sim

plest form that represents the total amount of money you spent
This is not a question but an apology. I sent a post stating the answer was wrong, but I'm wrong, because I read the problem carelessly, thinking it was a very similar problem I saw in a workbook. That problem also included that the brother also bought a bottle of water. My bad!
Mathematics
1 answer:
Sloan [31]3 years ago
3 0
The total cost is the sum of all the products that were purchased.
 We have then:
 For this case, the total cost is given by:
 C = 3x + 4.50
 Where,
 x: represents the cost of each water.
 Answer:
 
an expression in simplest form that represents the total amount of money you spent is:
 
C = 3x + 4.50
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If the ball rolled 20 meters in 5 secoundes whats its speed
MaRussiya [10]

Answer:

4 meters/ sec

Step-by-step explanation:

20/5 = 4 Lol

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2 years ago
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A student expressed the sum of 2 whole numbers as 5 times (8+3).What are the 2 whole numbers?
Marta_Voda [28]

Well if the two numbers are equal to 5x(8+3).

Lets say that these two numbers are X and Y,

So that would be X + Y = 5(8+3)

which means X + Y = 55

You could write that as a fuctions Y = 55 - X

Now by using the graph you get and the X values of [0,55] ( This means every value from 0 to 55 ), you will get a X and Y value that if you added up together will give you the value of 8(5+33)

An examples for the answers would be

(0,55) (1,54) (2,53) (3,52) (4,51) (5,50) (6,49) ... it goes on until x reaches 55.

8 0
3 years ago
Solve for m<br> 3m-4=5m+10
Sonbull [250]

Answer:

-7

Step-by-step explanation:

3m-4=5m+10

-2m-4=10

-2m=14

m=-7

7 0
2 years ago
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Joes apple weighs 4/5 martas apple weighs 0.5 how much more does joes weigh than martas
FromTheMoon [43]

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0.3

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In △ABC, m∠A=39°, a=11, and b=13. Find c to the nearest tenth.
Talja [164]

For this problem, we are going to use the <em>law of sines</em>, which states:

\dfrac{\sin{A}}{a} = \dfrac{\sin{B}}{b} = \dfrac{\sin{C}}{c}


In this case, we have an angle and two sides, and we are trying to look for the third side. First, we have to find the angle which corresponds with the second side, B. Then, we can find the third side. Using the law of sines, we can find:

\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{B}}{13}


We can use this to solve for B:

13 \cdot \dfrac{\sin{39^{\circ}}}{11} = \sin{B}

B = \sin^{-1}{\Big(13 \cdot \dfrac{\sin{39^{\circ}}}{11}\Big)} \approx 48.1


Now, we can find C:

C = 180^{\circ} - 48.1^{\circ} - 39^{\circ} = 92.9^{\circ}


Using this, we can find c:

\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{92.9^{\circ}}}{c}

c = \dfrac{11\sin{92.9^{\circ}}}{\sin{39^{\circ}}} \approx \boxed{17.5}


c is approximately 17.5.

8 0
2 years ago
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