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expeople1 [14]
3 years ago
12

Which of the following statements is true about what happens during a chemical reaction?

Chemistry
2 answers:
Alika [10]3 years ago
6 0

The correct answer is A. Bonds of the reactants are broken, and bonds of the products are formed.

tiny-mole [99]3 years ago
5 0

Answer: The correct option is A.

Explanation: In a chemical reaction, reactants react to form a number of products.

For the formation of products, the bonds of the individual reactants must be broken and the bonds of the products must be formed.

For example: Formation of water from hydrogen gas and oxygen gas. Reaction follows:

2H_2(g)+O_2(g)\rightarrow 2H_2O(l)

The Bonds of hydrogen and oxygen molecule are broken and new bonds between hydrogen and oxygen atoms are formed to give water molecule.

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Jacob's teacher shows his class a shaker filled with table salt. Jacob thinks that the salt in the shaker looks like a s
Elodia [21]
The answer would be c
6 0
3 years ago
8
mr_godi [17]

Answer:8

in the respiratory system

a.

Explanation:

7 0
2 years ago
For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coeffici
Brut [27]

<u>Question:</u>

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K

<u>Answer:</u>

The mean activity coefficient for HCl solution is 0.78.

<u>Explanation:</u>

Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is

              E=E_{0}-0.0514 \mathrm{V} \ln \gamma

As we know that E_{0} = 0.22 V and E = 0.342 V, the equation will become

             0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma

             0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)

             0.12 \mathrm{V}=-0.0514 \mathrm{V}(\ln \gamma+\ln 0.124)

             \frac{0.12}{0.0514}=-\ln (0.124 \gamma)

             -2.3346=\ln (0.124 \gamma)

             e^{-2.3346}=0.124 \gamma

             0.0968=0.124 \gamma

             \gamma=\frac{0.0968}{0.124}=0.78

So, the mean activity coefficient is 0.78.

6 0
3 years ago
In one experiment 7.62 g of Fe are allowed to react with 8.67 g of S
vichka [17]

calculate moles of both reagents given and the moles of FeS that each of them would form if they were in excess  

moles = mass / molar mass  

moles Fe = 7.62 g / 55.85 g/mol  

= 0.1364 moles  

1 mole Fe produces 1 mole FeS  

Therefore 7.62 g Fe can form 0.1364 moles FeS  

moles S = 8.67 g / 32.07 g/mol  

= 0.2703 moles S  

1 mole S can from 1 moles FeS  

So 8.67 g S can produce 0.2703 moles FeS  

The limiting reagent is the one that produces the least product. So Fe is limiting.  

The maximum amount of FeS possible is from complete reaction of all the limiting reagent.  

We have already determined that the Fe can form up to 0.1364 moles of FeS, so this is max amount of FeS you can get.  

Convert to mass

hope this helps :)

4 0
3 years ago
WILL GIVE BRAINLIEST!Which statement best describes electrolytic and voltaic cells?
Jlenok [28]

Answer:

the last answer is right.

3 0
3 years ago
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