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Vika [28.1K]
3 years ago
5

What is the oxidation number of chlorine in HClO4?

Chemistry
1 answer:
Elza [17]3 years ago
8 0

CIO4-=-1

CI=4O=-1

O has a 2- oxidation change so

CI+4(-2)=-1

CI+(-8)=-1

CI=-1+8=7

So the oxidation number of chlorine is 7 in this case

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Consider the following reaction. 3 Fe(s) + 4 H2O(g) Fe3O4(s) + 4 H2(g) At 900°C, Kc for the reaction is 5.1. If 0.050 mol of H2O
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Hello,

In this case, considering the given reaction:

3 Fe(s) + 4 H_2O(g) \rightleftharpoons Fe_3O_4(s) + 4 H_2(g)

Thus, for the equilibrium, just water and hydrogen participate as iron and iron(II,III) oxide are solid:

Kc=\frac{[H_2]^4}{[H_2O]^4}

Thus, at the beginning, the concentration of water is 0.05 M and consequently, at equilibrium, considering the ICE procedure, we have:

5.1=\frac{(4x)^4}{(0.05M-4x)^4}

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\sqrt[4]{5.1} =\sqrt[4]{[\frac{(4x)}{(0.05M-4x)}]^4}\\\\1.5=\frac{(4x)}{(0.05M-4x)}\\\\x=0.0075M

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Best regards.

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