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gogolik [260]
3 years ago
11

Describe your relationship with your parents in 100 words​

Chemistry
2 answers:
Svetlanka [38]3 years ago
6 0

Answer:

thats a lot to ask

Explanation:

ycow [4]3 years ago
3 0

Answer:

Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad Really Bad (sadly bad :( )

Explanation:

That's exactly 100 words :)

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The normal boiling point of a substance is defined to be the temperature at which the liquid phase of the substance is in equili
boyakko [2]

Answer:

ΔSv = 0.1075 KJ/mol.K

Explanation:

Binary solution:

∴ a: solvent

∴ b: solute

in equilibrium:

  • μ*(g) = μ(l) = μ* +RTLnXa....chemical potential (μ)

⇒ Ln (1 - Xb) = ΔG/RT

∴ ΔG = ΔHv - TΔSv

⇒ Ln(1 -Xb) = ΔHv/RT - ΔSv/R

∴ Xb → 0:

⇒ Ln(1) = ΔHv/RT - ΔSv/R

∴ T = T*b....normal boiling point

⇒ 0 = ΔHv/RT*b - ΔSv/R

⇒ ΔSv = (R)(ΔHv/RT*b)

⇒ ΔSv = ΔHv/T*b

∴ T*b = 80°C ≅ 353 K

⇒ ΔSv = (38 KJ/mol)/(353 K)

⇒ ΔSv = 0.1075 KJ/mol.K

5 0
3 years ago
Which of the following would dissolve in water?<br> CCl4<br> LiCl<br> CH4<br> PCl6
babymother [125]
Like dissolves like
so water is polar

CCl4 is nonpolar
LiCl is polar
CH4 is nonpolar
PCl6 is nonpolar

so LiCl would dissolve
7 0
3 years ago
Read 2 more answers
What coefficient would the O 2 have after balancing C 4 H 10 +O 2 CO 2 +H 2 O ?
nydimaria [60]

Answer: 6

Explanation:

6 0
3 years ago
A gas occupies 200ml at a temperature of 26 degrees Celsius and 76mmHg pressure. Find the volume at -3degree Celsius with the pr
sergey [27]

Answer:

184.62 ml

Explanation:

Let p_1, v_1, and T_1 be the initial and p_2, v_2, and T_2 be the final pressure, volume, and temperature of the gas respectively.

Given that the pressure remains constant, so

p_1=p_2 ...(i)

v_1 = 200 ml

T_1= 26 ^{\circ}C = 273+26 =299 K

T_2= 3 ^{\circ}C = 273+3 =276 K

From the ideal gas equation, pv=mRT

Where p is the pressure, v is the volume, T is the temperature in Kelvin, m is the mass of air in kg, R is the specific gas constant.

For the initial condition,

p_1v_1=mRT_1 \\\\mR= \frac{p_1v_1}{T_1}\cdots(ii)

For the final condition,

p_2v_2=mRT_2 \\\\mR= \frac{p_2v_2}{T_2}\cdots(iii)

Equating equation (i), and (ii)

\frac{p_1v_1}{T_1}=\frac{p_2v_2}{T_2}

\frac{v_1}{T_1}=\frac{v_2}{T_2}  [from equation (i)]

v_2=\frac{T_2}{T_1} \times v_1

Putting all the given values, we have

v_2=\frac{276}{299} \times 200 = 184.62 \; ml

Hence, the volume of the gas at 3 degrees Celsius is 184.62 ml.

7 0
3 years ago
Write a question about how changing temperature affects a gas.
UNO [17]
Which property of gas affects the gas by change in that property ?
7 0
3 years ago
Read 2 more answers
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