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natita [175]
3 years ago
14

Please helppp final quiz helppp!!!!

Chemistry
1 answer:
Anna71 [15]3 years ago
4 0

Answer:

8 N.

force= mass*acceleration

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Are people made up of matter? Do they have mass?
GaryK [48]
Yes. Everything is made up of mass. If it takes up space, it has mass
3 0
3 years ago
This image shows the development of what climate phenomenon?
Tpy6a [65]

Answer:

Rain shadow

Explanation:

Climate is the average weather condition of a place over a long period of time.

The image shows a rain shadow effect around a mountainous region. The type of rainfall controlled this way is known as an orographic rainfall.

  • On the leeward side which is the opposite side of where the rain cloud forms, there is dryness and lack of rainfall.
  • As moist air rises along the edge of the windward side, cloud forms.
  • This windward side receives a significant amount of rainfall
  • The windward side is hit with cold and dry wind and it is barren.
8 0
3 years ago
A solid mass of 25g is added to a solution with the mass of 60g. The final mass of the solution is 75g. Explain why the mass of
Ann [662]

It is not equal because it dose not obey the conservation of mass. 60+25= 85 not 75.

4 0
3 years ago
Helpppp!!!
OlgaM077 [116]

Answer:

your answer would be E

Explanation:

I took that class

3 0
2 years ago
Read 2 more answers
A piece of unknown metal with mass 30 g is heated to 110.0 °C and dropped into 100.0 g of water at 20.0 °C. The final temperatur
Ymorist [56]

<u>Answer:</u> The specific heat of metal is 0.821 J/g°C

<u>Explanation:</u>

When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]       ......(1)

where,

q = heat absorbed or released

m_1 = mass of metal = 30 g

m_2 = mass of water = 100 g

T_{final} = final temperature = 25°C

T_1 = initial temperature of metal = 110°C

T_2 = initial temperature of water = 20.0°C

c_1 = specific heat of metal = ?

c_2 = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

30\times c_1\times (25-110)=-[100\times 4.186\times (25-20)]

c_1=0.821J/g^oC

Hence, the specific heat of metal is 0.821 J/g°C

8 0
3 years ago
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