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GaryK [48]
3 years ago
11

Please help me with this someone

Mathematics
1 answer:
zepelin [54]3 years ago
3 0

Answer: The best estimate for this is 52.

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Find the perimeter of triangle ABC.
Harlamova29_29 [7]
By definition, the perimeter of the triangle is the sum of its sides.
 We must then use the formula of distance between points:
 d =  \sqrt{(x2-x1) ^ 2 + (y2-y1) ^ 2}
 We now look for the longitus for each of the sides:
 
 For L1:
 L1 = \sqrt{(6-2)^2 + (6-2)^2}
 L1 =  \sqrt{32} 

 L1 = 4\sqrt{2}

 For L2:
 L2 = \sqrt{(7-2)^2 + (-3-2)^2}
 L2 = \sqrt{50}
 L2 = 5\sqrt{2}

 For L3:
 L3 = \sqrt{(7-6)^2 + (-3-6)^2}
 L3 = \sqrt{82}
 
 Then, the perimeter is given by:
 P = L1 + L2 + L3
 Substituting values we have:
 P = 4\sqrt{2} + 5\sqrt{2} + \sqrt{82} 

P = 9\sqrt{2} + \sqrt{82}

 Answer:
 
the perimeter of triangle ABC is:
 
none of the above.
5 0
3 years ago
Read 2 more answers
PLEASE ITS DUE SOON HELP AGGGGGGGGGGG IM STRESSING
inna [77]

Answer:

B

Step-by-step explanation:

You have to add 7 to both sides to isolate the variable

4 0
3 years ago
Justin walked his dog 5 miles in
Ad libitum [116K]

Answer:

Is the 5 separate or to gather like 45

3 0
3 years ago
I need help ASAP! I will give your answer the brainiest answer
Korvikt [17]

This graph will start at (.5, 0) as the vertex.

To find this, all you need to do if find the point where inside the absolute value sign is equal to 0. Since the graph can never have a negative value, this will be the lowest point.

2x - 1 = 0

2x = 1

x = .5

From there, you can plot each point by going up two and to the left one.

Examples of Points: (1.5, 2) and (2.5, 4)

You can also plot the other side of the graph by going up two and to the right one.

These points can be found using the slope, which is the number attached to x (2).

Example of Points (-.5, 2) and (-1.5, 4).


8 0
3 years ago
Show your mastery of equivalent and simplifying fractions by using the sketchpad below to write the fraction
Sphinxa [80]
Answer: 2/3 (two thirds)

Explanation: Divide both denominator and numerator by the common factor of fourteen
3 0
3 years ago
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