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weeeeeb [17]
3 years ago
13

Can someone please tell me the answers but also explain how to do it? Thank you

Mathematics
1 answer:
11111nata11111 [884]3 years ago
5 0

Answer:

8: 90 degrees, 9: 165 degrees, 6: 81 degrees, 7: angles in the same segment are equal

Step-by-step explanation:

For question 8:

Notice how the line AB just barely touches the edge of the circle. We call this kind of line a tangent. The point O is at the center of the circle so the line OB is a radius. The angle between a tangent and a radius is always 90 degrees, so ABO is 90 degrees.

For question 9:

By the exact same logic as 8, ACO is also 90 degrees. The sum of interior angles in a 4 sided shape (a quadrilateral) is always 360 degrees. This means that 15 + 90 + 90 + x = 360 = 195 + x so x = 360 - 195 = 165

For question 6/7:

We use the theorem that the angles in the same segment are equal. This means that a is 81 degrees.

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The answer is A and B

Step-by-step explanation:

y-y=m(x-x)

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y+3=0.4(x+5)

y-y=m(x-x)

y-1=0.4(x-5)

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2 years ago
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Katen [24]

Answer:

Step-by-step explanation:

7*(7 + x+1) = 6*(x + 5 + 6)       {Intersecting secant theorem}

7 *(x + 8) = 6*(x + 11)

Distributive property,

7x + 56   = 6x + 66

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sleet_krkn [62]

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3 years ago
A. Find the linear approximating polynomial for the following function centered at the given point a. b. Find the quadratic appr
Tema [17]

Answer:

a. p1(x) = 2 - x

b. p2(x) = x² - 3*x + 3

c. p1(0.97) = 1.03; p2(0.97) = 1.0309

Step-by-step explanation:

f(x) = 1/x

f'(x) =  -1/x²

f''(x) = 2/x³

a = 1

a. The linear approximating polynomial is:

p1(x) = f(a) + f'(a)*(x - a)

p1(x) = 1/1 + -1/1² * (x - 1)

p1(x) = 1 - x + 1

p1(x) = 2 - x

b. The quadratic approximating polynomial is:

p2(x) = p1(x) + 1/2 * f''(a)*(x - a)²

p2(x) = 2 - x + 1/2 * 2/1³ * (x - 1)²

p2(x) = 2 - x + (x - 1)²

p2(x) = 2 - x + x² - 2*x + 1

p2(x) = x² - 3*x + 3

c. approximate 1/0.97 using p1(x)

p1(0.97) = 2 - 0.97 = 1.03

approximate 1/0.97 using p2(x)

p2(0.97) = 0.97² - 3*0.97 + 3 = 1.0309

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3 years ago
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