It means <span>θ is in fourth quardant.</span>
Answer:
8x+8y
Step-by-step explanation:
y + 3x + 4y + 2x + 3y +3x
<em>With</em><em> </em><em>this</em><em> </em><em>we</em><em> </em><em>group</em><em> </em><em>x</em><em> </em><em>with</em><em> </em><em>x</em><em> </em><em>and</em><em> </em><em>y</em><em> </em><em>with</em><em> </em><em>y</em><em> </em><em>and </em><em>in</em><em> </em><em>ascending</em><em> </em><em>order</em><em> </em><em>so</em><em> </em><em>x</em><em> </em><em>comes</em><em> </em><em>before</em><em> </em><em>y</em>
3x+2x+3x
And the y with y
y+4y+3y
Which is;
3x+2x+3x+y+4y+3y
8x+8y
Answer:
4 * 14
Step-by-step explanation:
Given
32 + 24
Required
Write as a product of two factors
First, we need to get the GCF of 32 and 24
The factors of 32 and 24 are:
The GCF (greatest common factor) is 8
So, the expression 32 + 24 can be rewritten as:
Add 8 + 6
Hence,
32 + 24 can be rewritten as 4 * 14
Answer:
<u>The solutions of the system ⇒ (-6 , 312) and (6 , 312)</u>
Step-by-step explanation:
Given:
10x² - y = 48 ⇒(1)
2y = 16x² + 48 ⇒(2)
From eq.(1) ⇒ y = 10x² - 48 ⇒(3)
By substitution with y from eq.(3) at eq.(2)
∴ 2(10x² - 48) = 16x² + 48
Solve for x
∴ 20x² - 96 = 16x² + 48
∴ 20x² - 16x² = 48 + 96
∴ 4x² = 144
∴ x² = 144/4 = 36
∴ x = ±√36 = ±6
By substitution with x at eq.(3)
when x = 6 ⇒ y = 10x² - 48 = 10 * 6² - 48 = 10 * 36 - 48 = 312
when x = -6 ⇒ y = 10x² - 48 = 10 * (-6)² - 48 = 10 * 36 - 48 = 312
<u>So, there are two solutions of the system which are (-6,312) and (6,312)</u>
