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Luba_88 [7]
3 years ago
14

For every action there is an equal and opposite reaction. What does these words mean in physics?

Physics
1 answer:
Ne4ueva [31]3 years ago
4 0

Answer:

The above given statement represent the Newton;'s 3rd law of motion.

This describes that when two objects collides or interacts with each other, there occurs a pair of forces that directly acts on the two colliding objects. The force exerted on both the sides are of equal magnitude.

For example, there are two contrasting body named M and N, which collides with each other. This collision results in the occurrence of force acting on both the objects. The body M exerts a force on body N and similarly, the body N exerts a force on body M, and this two forces are equal in amount.

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a ball thrown upward

Explanation:

it is the only thing that is picking up speed

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Groups of organs that work together to complete a process in the body are called:
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A block is projected up a frictionless inclined plane with initial speed v0 = 7.14 m/s. The angle of incline is θ = 36.5°. (a) H
Wewaii [24]

Answer:

(a)x=4.37m\\\\(b)t=1.225s\\\\(c) v_{f}=7.14m/s

Explanation:

Given data

v_{o}=7.14m/s\\\alpha =36.5^o

For Part (a)

Starting with the -ve acceleration of the body (opposite to the gravitational force)

a=-gSin\alpha \\a=-(9.8m/s^2)Sin(36.5)\\a=-5.83m/s^2

Using equation of motion

v_{f}^2=v_{o}^2+2ax\\(0m/s)^2=(7.14m/s)^2+2(-5.83m/s^2)x\\-(7.14m/s)^2=2(-5.83m/s^2)x\\x=\frac{-(7.14m/s)^2}{2(-5.83m/s^2}\\ x=4.37m

For Part (b)

Using the result in Part (a) we can substitute in other equation of motion to get time t:

x=\frac{1}{2}vt\\ 4.37m=\frac{1}{2}(7.14m/s)t\\ (7.14m/s)t=2*(4.37)\\t=8.744/7.14\\t=1.225s

For Part (c)

At state 2 where vo=0m/s and the acceleration is positive (same direction as the gravitational force)

a=gSin\alpha \\a=(9.8m/s^2)Sin(36.5)\\a=5.83m/s^2\\\\\\v_{f}^2=v_{o}^2+2ax\\v_{f}^2=(0m/s)^2+2(5.83m/s^2)(4.37m)\\v_{f}^2=50.95\\v_{f}=\sqrt{50.95}\\ v_{f}=7.14m/s

4 0
3 years ago
Https://student.masteryconnect
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Answer:

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ik.... ....... v

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3 years ago
In this image of a pendulum, where is the lowest potential energy found?
uranmaximum [27]

Think about the formula for potential energy. (Surely you remember it):

Potential energy = (mass) x (acceleration of gravity) x (height)

-- The mass on the end of the pendulum doesn't change.

-- The acceleration of gravity doesn't change.

-- The only thing that changes is the height of the mass on the end.

So the potential energy is lowest when its height is the lowest.

That's position <em>B </em>.

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