Answer
given,
diameter,d₁ = 7.5 cm
d₂ = 4.5 cm
P₁ = 32 kPa
P₂ = 25 kPa
Assuming, we have calculation of flow in the pipe
using continuity equation
A₁ v₁ = A₂ v₂
π r₁² v₁ = π r₂² v₂
Applying Bernoulli's equation
v₂ = 4.01 m/s
fluid flow rate
Q = A₂ V₂
Q = π (0.0225)² x 4.01
Q = 6.38 x 10⁻³ m³/s
flow in the pipe is equal to 6.38 x 10⁻³ m³/s
Explanation:
It is given that,
Let Charge of
is taken from points A & B such that
.
We need to find the energy of charge. Electric potential is defined as the work done per unit of electric charge. So,

So, the energy of charge decreases by
. Hence, the correct option is (a).
As you gave no pic I took them on one lined
- F_1=3N
- F_2=10N
- F_3=3root 3 N
- F_4=6N





It would either break or stop depends on the density