Answer:
Approximately
(assuming that the projectile was launched at angle of
above the horizon.)
Explanation:
Initial vertical component of velocity:
.
The question assumed that there is no drag on this projectile. Additionally, the altitude of this projectile just before landing
is the same as the altitude
at which this projectile was launched:
.
Hence, the initial vertical velocity of this projectile would be the exact opposite of the vertical velocity of this projectile right before landing. Since the initial vertical velocity is
(upwards,) the vertical velocity right before landing would be
(downwards.) The change in vertical velocity is:
.
Since there is no drag on this projectile, the vertical acceleration of this projectile would be
. In other words,
.
Hence, the time it takes to achieve a (vertical) velocity change of
would be:
.
Hence, this projectile would be in the air for approximately
.
Answer:
20 seconds.
Explanation:
The following data were obtained from the question:
Distance = 10 m
Speed = 0.5 m/s
Time =...?
The speed of an object is simply defined as the distance travelled by the object per unit time. Mathematically, it is expressed as:
Speed = Distance /time
With the above formula, we can obtain the time taken for the ball to travel a distance of 10 m as shown below:
Distance = 10 m
Speed = 0.5 m/s
Time =...?
Speed = Distance /time
0.5 = 10/time
Cross multiply
0.5 × time = 10
Divide both side by 0.5
Time = 10/0.5
Time = 20 secs.
Therefore, it will take 20 seconds for the ball to travel a distance of 10 m.
We can use the equation for kinetic energy, K=1/2mv².
Your given variables are already in the correct units, so we can just plug in the variables and solve for v.
K = 1/2mv²
16 = 1/2(2)v²
16 = (1)v²
√16 = v
v = 4 m/s
Therefore, the velocity of a 2 kg mass with 16 J of kinetic energy is 4 m/s.
Hope this is helpful!
Explanation:
Let
is the mass of proton. It is moving in a circular path perpendicular to a magnetic field of magnitude B.
The magnetic force is balanced by the centripetal force acting on the proton as :

r is the radius of path,

Time period is given by :


Frequency of proton is given by :

The wavelength of radiation is given by :


So, the wavelength of radiation produced by a proton is
. Hence, this is the required solution.