Answer:
increasing
Explanation:
Given that,
Initial angular speed =1 rad/s
Angular acceleration = 0.5 rad/s²
We know that the angular acceleration is given by :
Where
city and t is time is the final angualr velo
As the angular acceleration of the object is positive. It means that the final speed of the object is more than that initial. As a result, the speed of its rotation is increasing.
A stream’s discharge rate if it has a width of 10 meters, a depth of 2 meters, and a velocity of 2 meters per second will be 40 /sec .
Discharge rate = velocity * area
= velocity * depth * width
= 2 * 2 * 10 = 40 /sec
A stream’s discharge rate if it has a width of 10 meters, a depth of 2 meters, and a velocity of 2 meters per second will be 40 /sec .
learn more about discharge rate
brainly.com/question/20709500?referrer=searchResults
#SPJ4
According to the <u>Third Kepler’s Law of Planetary motion</u> “<em>The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”.</em>
In other words, this law states a relation between the orbital period of a body (moon, planet, satellite) orbiting a greater body in space with the size
of its orbit.
This Law is originally expressed as follows:
Where;
is the Gravitational Constant and its value is
is the mass of Jupiter
is the semimajor axis of the orbit Io describes around Jupiter (assuming it is a circular orbit, the semimajor axis is equal to the radius of the orbit)
If we want to find the period, we have to express equation (1) as written below and substitute all the values:
Then:
Which is the same as:
Therefore, the answer is:
The orbital period of Io is 42.482 h