Answer:
force = 11.33 
Explanation:
given data:
sled mass = 17.0 kg
inital velocity (U) = 4.10 m/s
elapsed time (T) 6.15 s
final velocity (V) = 0
final momentum P2 = 0
Initial momentum of sledge is


from newton second law of motion


Kgm/s^2
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Answer:
The rate of heat conduction through the layer of still air is 517.4 W
Explanation:
Given:
Thickness of the still air layer (L) = 1 mm
Area of the still air = 1 m
Temperature of the still air ( T) = 20°C
Thermal conductivity of still air (K) at 20°C = 25.87mW/mK
Rate of heat conduction (Q) = ?
To determine the rate of heat conduction through the still air, we apply the formula below.


Q = 517.4 W
Therefore, the rate of heat conduction through the layer of still air is 517.4 W
Answer:
Incomplete question, check attachment for completed question
Explanation:
The force of attraction between two forces are given as
F=kQq/r²