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Veseljchak [2.6K]
3 years ago
14

Please helpppppp, i'm stuck

Mathematics
2 answers:
Alex787 [66]3 years ago
4 0

4x plus 2 equal to 10

4x equal to 10 minus 2 which is 8

X is equal to 4 divided by 8

X is equal to 2

The opposite operations are subtraction and division

nata0808 [166]3 years ago
3 0

Answer:

The operations you see with you eyes are multiplication and addition.

4 times X plus 2 = 10

The operations you don't see are Subtraction and Division.

4x+2=10

Subtract 2 from both sides.

4x+2−2=10−2

4x=8

Divide both sides by 4.

4x/4  =  8/4

x=2

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Answer:

-12

Step-by-step explanation:

r = -3

4/9 * (-3) = -4/3

-4/3 * (-3) = 4

so, 4 * (-3) = -12

7 0
2 years ago
Find the missing side<br> Please help thank you!!
Savatey [412]

Answer:

c= \sqrt{41}

Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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3 years ago
A teacher has two students, one two times as old as the other. The teacher is five times as old as the older student, and in 5 y
kramer
Let's call the younger student's age A and the older student's age B. The teacher's age will be T.

B = 2A
T = 5B
T+5 = 5(A+5)

Simplify the last equation.

T+5 = 5A+25
T = 5A+20

Now we have two equations solved for T, so we can set them equal to each other.

5B = 5A + 20

We can plug 2A in for B

5(2A) = 5A + 20

10A = 5A + 20

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To find T, we plug 4 in for A in T = 5A + 20

T = 5(4) + 20

T = 40

The answer is 40 years old.


6 0
3 years ago
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Write a definite integral that represents the area of the region. (Do not evaluate the integral.)
joja [24]

Answer:

\int_{-1}^{1}7(x^{3}-x)\:dx

Step-by-step explanation:

1)  The other curve is y=0 then the common points of both curves are x-intercepts, the roots of y=7(x^{3}-x)

y=7(x^{3}-x)\Rightarrow 7(x^3-x)=0 \Rightarrow 7(x^{3}-x)=7x(x-1)(x-1)\Rightarrow \\S=\left ( 0,0 \right ),\left ( -1,0 \right ),\left ( 1,0 \right )

2). Then those intersection points are the upper and the lower limits. Plugging in to this formula for they belong to the interval [-1,1]:

\int_{a}^{b}|f(x)-g(x)dx

\int_{a}^{b}|f(x)-g(x)dx \Rightarrow \int_{-1}^{1}|7(x^{3}-x)-0|dx \Rightarrow \int_{-1}^{1}7(x^{3}-x)\:dx

 

8 0
3 years ago
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