Answer:
$600.29.
Step-by-step explanation:
At the end of each month the value is multiplied by 107% = 1.07.
So after 6 months the value is 400(1.07)^6
= $600.29.
They should me number 29’
So you want to set up an equation for a weighted average. You know the final is 30% of the grade, so everything else is 70%. This gives you:
(Final)(.30) + (other grades)(.70) = course grade
The best grade the student can get would be if they get a hundred on the final, since that’s the best score you can make on the final. Then,
(100)(.30) + (82)(.70) = course grade
30 + 57.4 = course grade = 87.4 Which, If you round, the student would get an 87.
For the last part, we use the same equation, just filling in different parts.
(Final)(.30) + (other grades)(.70) = course grade
This time, we don’t know the grade for the final, but we know the course grade.
(Final)(.30) + (82)(.70) = 75
(Final)(.30) + 57.4 = 75
(Final)(.30) = 17.6
Final = (17.6)/(.30)
Final = 58.667 Which is approx a 59.
It totally depends on speed at which train is moving.
If the speed of train is below 100 miles per hour the minimum distance maintained should be 4 feet.
If the speed of train is above 100 miles per hour and less than 125 miles per hour the minimum distance maintained should be 6.6 feet.(Approx)
As , when a train is moving with velocity more than this i.e above 125 miles per hour the minimum distance should be 15 feet.(Approximately)
Option (C) 15
Answer: 2/6
Step-by-step explanation:
One can be 2/6 because if multiply 1/3 by x for the numerator and the denomanator it is 2/6 and 2/6 is equivalent to 1/3
