Whisper-20dB
Quiet Residence-30dB
Soft stereo in Residence-40dB
Average Speech-60dB
Cafeteria-80dB
Pneumatic Jackhammer-90dB
Loud crowd noise-100dB
Accelerating Bike-100dB
Rock concert-120dB
Jet Engine (75 ft away)-140dB
(1)Mode=100dB (since 100 is occurring the maximum no. of times, i.e. it has the highest frequency of 2)
(2)Mean=sum of observations/Total number of observations
=(20+30+40+60+80+90+100+100+120+140)/10
=770/10=10dB
(3)Median= 1/2[{n/2}th observation + {(n/2)+1}th observation], where, n=total no. of observations
So, 1/2[{10/2}th observation + {(10/2)+1}th observation]
=1/2[5th observation+6th observation]
=1/2[80+90] [Because:5th observation=80dB and 6th=90dB]
=1/2(170)
=85
Therefore, median=85dB
The total interest earned is 40.75 and the final balance is 65.75
<u>Solution:</u>
Given, principle amount P = 25
Interest rate 
Times compounded per year n = 12
Time in years t = 30
On substituting the values we get
![A = 25 [ 1+ \frac{0.0325}{12}]^{12\times30}= 25 [2.63]= 65.75](https://tex.z-dn.net/?f=A%20%3D%2025%20%5B%201%2B%20%5Cfrac%7B0.0325%7D%7B12%7D%5D%5E%7B12%5Ctimes30%7D%3D%2025%20%5B2.63%5D%3D%2065.75)
Interest I = A - P [since, A = P+I]
Answer:
7 1/8
4 + 7/8 + 2 + 1/4
4+2=6
7/8 + 1/4=9/8 and 9/8 is equal to 1 1/8
6+1+1/8= 7 1/8
Answer:
3:42
Step-by-step explanation:
Add 57 minutes to 2:45
2:45
57
--------------
2:102
but there are 60 minutes in 1 hours so subtract 60 minutes and add 1 hour
2: 102
+1 -60
------------
3:42
You will end at 3:42
Your answer will be A. (8,1)
