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3 years ago

What ordered pair is a solution of this equation 3x-7y=28 help

1 answer:

5 0

put it in slope intercet form then take the number before the x and the number after the x and put them into an ordered pair.

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Find the area of a rectangle whose perimeter is 60in and width is 10in.

Dafna1 [17]

Answer:

250 sq. inch

Step-by-step explanation:

Perimeter: 60 inch

: 2 X L+B

: 2 X ? + 10

Length: 60-10

: 50/2

: 25 inch

Area: L X B

: 25 X 10

: 250 sq.inch

Hope it helps ;)

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3 0

2 years ago

3. Use this graph to

Step2247 [10]

Answer:

def b

Step-by-step explanation:

6 0

2 years ago

What is the area of this figure?

n200080 [17]

Answer:

243 cm^2 + 108 cm^2 = 351 cm^2

Step-by-step explanation:

So, we have a rectangle and two triangles, we know all the sides or angles.

Rectangle: with 9 cm lenght 15cm + 12 cm = 27 cm

Formula: A=wl -> A=9*27 = 243 cm^2

Trianlge: A=ab/2

Angle 90°

Side A 12 cm

Side B 18 cm - 9 cm = 9 cm

A=ab/2=12·9/2=54 cm times 2 (for the opposite side) = 108 cm^2 = 351 cm^2

6 0

2 years ago

a theater is designed with 15 seats in the first row, 19 in the second, 23 in the third, and so on. if this seating pattern cont

marusya05 [52]

Answer:

131 seats are in the 30th row.

Step-by-step explanation:

The theater is designed with the first row there are 15 seats, in second row 19 seats and in the third row there are 23 seats.

Now, to find the number of seats in the 30th row.

So, we get the common difference( $d$ ) from the arithmetic sequence first:

$19-15=4.$

Thus, $d=4.$

So, the first tem $a(1)$ = 15.

The number of last row ( $n$ ) = 30.

Now, to get the number of seat in the 30th row we put formula:

$a(n) = a(1) + d(n-1)$

$a(30)=15+4(30-1)$

$a(30)=15+4\times 29$

$a(30)=15+116$

$a(30)=131$

Therefore, 131 seats are in the 30th row.

4 0

3 years ago

Where is the point of discontinuity of y = -4x+81/x-2 ?

Genrish500 [490]

Answer:

x = 2

Step-by-step explanation:

y = $\frac{-4x+81}{x-2}$

If the denominator is equal to zero , then y is undefined.

this discontinuity can be found by equating the denominator to zero and solving for x.

x - 2 = 0 ⇒ x = 2 is the point of discontinuity

4 0

2 years ago