Answer:
a) 
b) 
c) 
Explanation:
a)
when
is added to LiOH, lithium chlorate and water is formed.

Balancing of above reaction,
It can be seen that all the atoms in both the sides are balanced. so it is a balanced reaction.
(b) When aqueous
is added to NaOH,
and
is formed. It is a neutrilization reaction.

Balancing of above reaction,
First balance all the atoms except O and H
S atom is already balanced in either side
No. of Na atom in left hand side = 1
No. of Na atom in right hand side = 2
So multiply NaOH by 2, now the reaction becomes:

No. of O atoms in left hand side = 6
No. of O atoms in right hand side = 5
So multiply H2O by 2, now the reaction becomes:

Now, it can been seen that all the atoms are balanced.
c) When
reacts with HF, baroum fluoride and water is formed.

Balancing of above reaction,
Barium atoms are already balanced on either side.
No. of F atoms on left hand side = 1
No. of F atoms on right hand side = 2
So, multiply HF by 2, now reaction becomes

In order to balance H and O on either side, multiply H2O by 2.
