Answer:
1. 179.2 L
2. 303.62 g
Explanation:
1. Determination of volume of H₂O (g).
We'll begin by calculating the number of mole in 144 g of H₂O. This is illustrated below:
Mass of H₂O = 144 g
Molar mass of H₂O = (2×1) + 16 = 2 + 16 = 18 g/mol
Mole of H₂O =?
Mole = mass /Molar mass
Mole of H₂O = 144/18
Mole of H₂O = 8 moles
Finally, we shall determine volume of H₂O (g) as follow:
1 mole of any gas occupy 22.4L at stp.
Therefore, 8 moles of H₂O (g) will occupy =
8 × 22.4 = 179.2 L
Thus, 144 g of H₂O (g) occupies 179.2 L
2. Determination of the mass of H₂O₂ (g).
We'll begin by calculating the number of mole of H₂O₂ (g) that occupied 200 L at STP. this can be obtained as follow:
1 mole of any gas occupy 22.4 L at stp.
Therefore, Xmol of H₂O₂ (g) will occupy 200 L at STP i.e
Xmol of H₂O₂ (g) = 200/22.4
Xmol of H₂O₂ (g) = 8.93 moles
Thus, 8.93 moles of H₂O₂ (g) occupied 200 L at STP.
Finally, we shall determine the mass of H₂O₂ (g) as follow:
Mole of H₂O₂ (g) = 8.93 moles
Molar mass of H₂O₂ = (2×1) + (2×16) = 2 + 32 = 34 g/mol
Mass of H₂O₂ =?
Mole = mass /Molar mass
8.93 = mass of H₂O₂ /34
Cross multiply
Mass of H₂O₂ = 8.93 × 34
Mass of H₂O₂ = 303.62 g
