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DIA [1.3K]
3 years ago
9

8. 36.8 = [11.5 – (2.5 X 3)]2

Mathematics
1 answer:
Anestetic [448]3 years ago
6 0

Answer:

[11.5-(2.5*3)]^2=16

Step-by-step explanation:

We want to evaluate [11.5-(2.5*3)]^2

Let us evaluate within the parenthesis first:

[11.5-(2.5*3)]^2=[11.5-(7.5)]^2

\implies [11.5-(2.5*3)]^2=[11.5-7.5]^2

We again subtract within the bracket to obtain:

[11.5-(2.5*3)]^2=[4]^2

This finally gives us:

[11.5-(2.5*3)]^2=16

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A boat can travel 496 km on 124 liters of fuel. How much fuel will it need to go 84 km?
Anika [276]

Answer:

A boat would need 21 liters to cover the distance of 84 km.

Step-by-step explanation:

Given

A boat can travel 496 km on 124 liters of fuel.

To determine

How much fuel will it need to go 84 km?

It is stated that:

Distance covered in 124 liters of fuel = 496 km

Thus,

Unit rate = 496 km / 124 liters

               = 4 km per liter

Thus,

The distance covered in 1 liter = 4km

In order to determine the distance covered in 84 km, all we need is to divide 84 km by 4.

i.e.

The fuel needed to go 84 km = 84 / 4 = 21 liters

Therefore, a boat would need 21 liters to cover the distance of 84 km.

7 0
3 years ago
Find the slope of the line that passes through (-34, 72) and (31, 27).
ZanzabumX [31]
The answer i got is -9/13
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Which best describes the strength of the correlation, and
denis23 [38]

Answer:

Step-by-step explanation:

the answer is ~ It is a weak negative correlation, and it is likely causal.

7 0
3 years ago
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The total charge on 7 particles is −42 units. All the particles have the same charge.
qwelly [4]
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5 0
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Solve the equation : 8+10^x=1008
Marizza181 [45]
Hi there.

I'm just going to put the answer for now. I might come back and edit my answer if I figure out how to solve this the long way.

All I did was figure out what exponent you raise 10 to. 

10³ = 1000

So, we now have 8 + 10³ = 1008

Edit:

I did it on paper - here it is broken down.

8 + 10^{x} = 1008

Subtract 8 from both sides.

10^{x} = 1000

We know that 10³ = 1000

<em>x</em> = 3

~
7 0
3 years ago
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