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3 years ago

I need help please ?!!!!!

Mathematics

1 answer:

allsm [11]3 years ago

5 0

Answer:

-6x² - x + 35

The answer is The Last One

Step-by-step explanation:

Hope This Helps :)

Plz Mark Brainliest!!!

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Your favorite video game just went on sale for 33% off.

abruzzese [7]

Answer:

$40.20

Step-by-step explanation:

60 / 100 = 0.6

0.6 x 33 = 29.8

60 - 29.8 = 40.2

Thus he price after the discount would be $40.20

3 0

3 years ago

The number 0.1111... repeats forever; therefore, it is irrational. True or False.

Rasek [7]

Answer is True. We cannot write it in rational form where both numbers are finite integers. In this case we cannot represent this number as fraction of finite integers therefore it is irrational.

6 0

3 years ago

Read 2 more answers

What is the formula to calculate the surface area of a rectangular prism with a cube removed?

ch4aika [34]

2ab + 2bc + 2ac the formula for the rectangular prism and i'm guessing you would find the answer to this than you would find your formula for the cube which is 6 a 2 and you would find that answer.
You would take your total for the rectangular prism answer and subtract the cube answer from it and you would probably get your answer.
hope that helped?!
:)

3 0

3 years ago

Shortern this expression pls

pogonyaev

Answer:

$c =\frac{8}{3}$

Step-by-step explanation:

Given

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}$

Required

Shorten

We have:

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}$

Rationalize

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7} * \frac{4 + \sqrt 7}{4 + \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}*\frac{4 - \sqrt 7}{4 - \sqrt 7}}$

Expand

$c = \sqrt{\frac{(4 + \sqrt 7)^2}{4^2 - (\sqrt 7)^2}} + \sqrt{\frac{(4 - \sqrt 7)^2}{4^2 - (\sqrt 7)^2}$

$c = \sqrt{\frac{(4 + \sqrt 7)^2}{16 - 7}} + \sqrt{\frac{(4 - \sqrt 7)^2}{16 - 7}$

$c = \sqrt{\frac{(4 + \sqrt 7)^2}{9}} + \sqrt{\frac{(4 - \sqrt 7)^2}{9}$

Take positive square roots

$c =\frac{4 + \sqrt 7}{3} + \frac{4 - \sqrt 7}{3}$

Take LCM

$c =\frac{4 + \sqrt 7 + 4 - \sqrt 7}{3}$

Collect like terms

$c =\frac{4 + 4+ \sqrt 7 - \sqrt 7}{3}$

$c =\frac{8}{3}$

4 0

3 years ago

2x(squared) + 23x-19=0

Helen [10]

Use quadratic formula

for ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

given
2x^2+23x-19=0
a=2
b=23
c=-19

x= $\frac{-23+/- \sqrt{23^2-4(2)(-19)} }{2(2)}$
x= $\frac{-23+/- \sqrt{529-152} }{4}$
x= $\frac{-23+/- \sqrt{377} }{4}$

x= $\frac{-23+ \sqrt{377} }{4}$ or $\frac{-23- \sqrt{377} }{4}$

7 0

3 years ago