Answer:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
- d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
- After first dose residual drug amount is:
d= 500*0.045= 22.5 mg
- After second dose:
d= 22.5*2= 45 mg
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
Distribute 2y to both 3y and 17
• 6y+34= 12
then you subtract 34 on both sides and get:
• 6y=-22
Finally you divide 6y on both sides and end up with:
y= -11/3 as a fraction
Hope this helped!
Y=3x-5
Y=5/4x+3/4
The solution to the equations is in the picture
