Solve 3x+4+7x+8+7x3+7x3

Nora must create a 4-character password to login to a website. The password must have three letters followed by a single digit,

patriot [66]

Answer:

The outcomes are {1nor} , {2nor}, {3nor}, {4nor}, {5nor}, {6nor}, {7nor}, {8nor}, {9nor}

Step-by-step explanation:

The outcomes are {1nor} , {2nor}, {3nor}, {4nor}, {5nor}, {6nor}, {7nor}, {8nor}, {9nor}

Reason-

0 can not be possible because if 0 is the first digit then , it will become the 3-digit password , not 4-digit

3 0

2 years ago

At the end of the day, Mr. Díaz drains the pool. The equation

Charra [1.4K]

Answer: 6 minutes.

Step-by-step explanation: You can use a graphing calculator to see the exact graph, but you're trying to figure out what value of x gives you a y of 0. -50 times 6 is 300, plus 300 equals 0.

7 0

2 years ago

Let P(x) be the statement"x= x2", If the domain consists of the integers, what are these truth values? (a) P(0) (b) P(1) (c) P(2

jeka57 [31]

Answer: i guess the problem is with P(x) => "x = $x^{2}$ ", then P(x) is true if that equality is true, and is false if the equality is false.

so lets see case for case.

a) x = 0, and $0^{2}$ = 0. So p(0) is true.

b) x = 1 and $1^{2}$ = 1, so P(1) is true.

c) x = 2, and $2^{2}$ = 4, and 2 ≠ 4, then P(2) is false.

d) x= -1 and $1^{2}$ = 1, and 1 ≠ -1, so P(-1) is false.

6 0

2 years ago

The sum of the lengths of two sides of a triangle is always greater then the length of the third side.

Tanya [424]

Answer:Triangle Inequality Theorem. The sum of the lengths of any two sides of a triangle is greater than the length of the third side

Step-by-step explanation:

5 0

3 years ago

A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random

Yuliya22 [10]

Answer:

b) independent samples t-test

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

Step-by-step explanation:

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2\neq 0$

Our notation on this case :

$n_1 =5$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

We can calculate the mean and deviation for eaach group with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_1 =5.92$ represent the sample mean for the group 1

$\bar X_2 =5.74$ represent the sample mean for the group 2

$s_1=1.88$ represent the sample standard deviation for group 1

$s_2=1.81$ represent the sample standard deviation for group 2

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}$

And now we can calculate the statistic:

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

The degrees of freedom are given by:

$df=5+5-2=8$

And now we can calculate the p value using the altenative hypothesis:

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

7 0

3 years ago