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4 years ago

Name a pair of fractions that use the least common denominator and are equivalent to 9/10 and 5/6.

2 answers:

6 0

A pair of fractions that use a least common denominator and that are equivalent to 9/10 and 5/6 are 27/30 (equivalent to 9/10) and 25/30 (equivalent to 5/6). Hope it helps :)

Zinaida [17]4 years ago

3 0

There is 27/30 and 24/30 these are equivalent and have common denomonators

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The area of a triangle is 32

Serhud [2]

We have the formula A = (h x b) / 2, where A is the area of the triangle, h is the height of the triangle, b is the base of the triangle;
So, 32 =(8 x b) / 2;
Then, 64 = 8 x b;
b = 64 ÷ 8;
b = 8 inches;

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4 years ago

Two angles are complementary. The first angle is 2x degrees. The second angle is (x+30) degrees. Determine the larger angle

Molodets [167]

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3 years ago

The perimeter of a rectangle is 141 feet, and the length is twice the width. What are the dimensions of the rectangle?

JulijaS [17]

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4 years ago

If you spin the spinner 7 times,what is the best prediction possible for the number of times it will land on pink?

Tems11 [23]

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3 years ago

At a cell phone assembly plant, 77% of the cell phone keypads pass inspection. A random sample of 111 keypads is analyzed. Find

Serggg [28]

Answer:

The probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}=p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

Let p = the proportion of keypads that pass inspection at a cell phone assembly plant.

The probability that a randomly selected cell phone keypad passes the inspection is, p = 0.77.

A random sample of n = 111 keypads is analyzed.

Then the sampling distribution of $\hat p$ is:

$\hat p\sim N(p,\ \sqrt{\frac{p(1-p)}{n}})\\\Rightarrow \hat p\sim N (0.77, 0.04)$

Compute the probability that the proportion of passed keypads is between 0.72 and 0.80 as follows:

$P(0.72$

$=P(-1.25$

Thus, the probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.

8 0

4 years ago